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3 years ago

What is the interquartile range of this set of data? 15, 19, 20, 25, 31, 38, 41

1 answer:

8 0

First, you have to find the median, which is the number in the middle: 25

Then cut the data in half by the median, so your new data sets are
15,29,20
and
31,38,41

Now you find the median of both of those sets, which is 29 and 38.

The interquartile range is the difference between the numbers, so 38-29 = 9.

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Step-by-step explanation:

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My son is seven times older than my grandson and I am 12 times older than my grandson. If you add all our ages together, the sum

Andrej [43]

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3 years ago

Estimate the solution to the system of equations 7x−y=7 x+2y=6 i need help

Yanka [14]

Answer:

(4/3, 7/3)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients
Coordinates (x, y)
Solving systems of equations of using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

7x - y = 7

x + 2y = 6

Step 2: Rewrite Systems

Equation: x + 2y = 6

[Subtraction Property of Equality] Subtract 2y on both sides: x = 6 - 2y

Step 3: Redefine Systems

7x - y = 7

x = 6 - 2y

Step 4: Solve for y

Substitution

Substitute in x: 7(6 - 2y) - y = 7
Distribute 7: 42 - 14y - y = 7
Combine like terms: 42 - 15y = 7
[Subtraction Property of Equality] Subtract 42 on both sides: -15y = -35
[Division Property of Equality] Divide -15 on both sides: y = 7/3

Step 5: Solve for x

Define original equation: x + 2y = 6
Substitute in y: x + 2(7/3) = 6
Multiply: x + 14/3 = 6
[Subtraction Property of Equality] Subtract 14/3 on both sides: x = 4/3

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3 years ago

What is the value of a in the equation 5a -10b = 45 when b = 3

leva [86]

Salutations!

$5a-10b = 45$

value of $b = 3$

Multiply 10 and 3

$10*3=30$

Now, you can solve the equation --

$5a-30=45$

separate the variables aside, and the numbers aside.

$5a=45 +30$

$5a=75$

$a=75/5$

$a=15$

Hope I helped (:

Have a great day!

6 0

3 years ago