Answer:
6/3 - c
Step-by-step explanation:
Answer:
sorry if I'm wrong but I think its a=1/6
So distribute using distributive property
a(b+c)=ab+ac so
split it up
(5x^2+4x-4)(4x^3-2x+6)=(5x^2)(4x^3-2x+6)+(4x)(4x^3-2x+6)+(-4)(4x^3-2x+6)=[(5x^2)(4x^3)+(5x^2)(-2x)+(5x^2)(6)]+[(4x)(4x^3)+(4x)(-2x)+(4x)(6)]+[(-4)(4x^3)+(-4)(-2x)+(-4)(6)]=(20x^5)+(-10x^3)+(30x^2)+(16x^4)+(-8x^2)+(24x)+(-16x^3)+(8x)+(-24)
group like terms
[20x^5]+[16x^4]+[-10x^3-16x^3]+[30x^2-8x^2]+[24x+8x]+[-24]=20x^5+16x^4-26x^3+22x^2+32x-24
the asnwer is 20x^5+16x^4-26x^3+22x^2+32x-24
Answer:
x=-8
(-8,-7)
Step-by-step explanation:
–9x + 9y = 9
–9x + 9(-7) = 9 (y=-7)
-9x-63=9
Both side +63
-9x=63+9
-9x=72
Both side divide -9
x=-8
y=-7
(-8,-7)
Answer:
Step-by-step explanation:
My recommendation is try to find a finals for both pre-algebra or algebra after learning some of the material ahead of time and after taking them, find which one is more comfortable for you
Good luck!
