Answer:
let y = 0 and solve for the other variable, because any point on x-axis has y-coordinate = 0
Answer:
a) 90 boxes
b) 27 boxes
Step-by-step explanation:
Please see the attached picture for the full solution.
Answer:
990, C
Step-by-step explanation:
The formula for the surface area of the bottom cushion is
A = 2wl + 2lh + 2hw (w is width, l is length, h is height)
w = 18, l = 21, h = 3
A = 2(18)(21) + 2(21)(3) + 2(3)(18)
A = 2(378) + 2(63) + 2(54)
A = 756 + 126 + 108
A = 990 (C)
Answer:
x=y+v/b
Step-by-step explanation:
So first you have y=x-v/b. You want to isolate x, so subtract x from both sides. You'll get -x+y=-v/b. Next, you're going to want to subtract y to further isolate x now that it's on the left side. Now you'll have -x=-y-v/b. But you don't want x to be negative, so you can divide both sides by -1 to make x positive. Now you'll have x=y+v/b.
Answer:
The probability that Aaron goes to the gym on exactly one of the two days is 0.74
Step-by-step explanation:
Let P(Aaron goes to the gym on exactly one of the two days) be the probability that Aaron goes to the gym on exactly one of the two days.
Then
P(Aaron goes to the gym on exactly one of the two days) =
P(Aaron goes to the gym on Saturday and doesn't go on Sunday) +
P(Aaron doesn't go to the gym on Saturday and goes on Sunday)
- If Aaron goes to the gym on Saturday the probability that he goes on Sunday is 0.3. Then If Aaron goes to the gym on Saturday the probability that he does not go on Sunday is 1-0.3 =0.7
- Since the probability that Aaron goes to the gym on Saturday is 0.8,
P(Aaron goes to the gym on Saturday and doesn't go on Sunday) =
P(the probability that Aaron goes to the gym on Saturday)×P(If Aaron goes to the gym on Saturday the probability that he does not go on Sunday)
=0.8×0.7=0.56
- The probability that Aaron doesn't go to the gym on Saturday is 1-0.8=0.2
- And if Aaron does not go to the gym on Saturday the probability he goes on Sunday is 0.9.
Thus, P(Aaron doesn't go to the gym on Saturday and goes on Sunday) = P(The probability that Aaron doesn't go to the gym on Saturday)×P(if Aaron does not go to the gym on Saturday the probability he goes on Sunday)
=0.2×0.9=0.18
Then
P(Aaron goes to the gym on exactly one of the two days) =0.56 + 0.18 =0.74
