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3 years ago

A single, six-sided die is rolled. Find the probability of rolling an even number or a number less than 6 .

Mathematics

1 answer:

boyakko [2]3 years ago

5 0

Answer:

P=1

Step-by-step explanation:

P(even or less than 6) = P(even)+P(less than 6) -P(even ∩ less than 6)

P(even)=3/6 (numbers 2,4, and 6)

P(less than 6) =5/6 (numbers 1,2,3,4, and 5)

P(even ∩ less than 6)=2/6 (numbers 2 and 4)

(3/6)+(5/6) -(2/6) = (3+5-2)/6 = 6/6=1

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$CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}$

Step-by-step explanation:

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3 years ago

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3 years ago

A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021

egoroff_w [7]

The sum of the given series can be found by simplification of the number

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A is approximately <u>2020.022</u>

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The given sequence is presented as follows;

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Therefore;

$\displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}$

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

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Therefore, for the last term we have;

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$\displaystyle \frac{A}{2} = 1011 \cdot \left(1 - \frac{1}{2022} \right)$

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