Answer:
a) 0.4164
Step-by-step explanation:
Mean lifespan (μ) = 18.8 days
Standard deviation (σ) = 2 days
For any given lifespan 'X', the z-score is:

For X=12.04 days:

A z-score of -3.38 falls in the 0.036-th percentile of a normal distribution.
For X=18.38 days:

A z-score of -3.38 falls in the 41.68th percentile of a normal distribution.
The probability that a butterfly lives between 12.04 and 18.38 days is

Answer:
The answer is b. x= 2, -1
Answer:
x = 5 cos 2t
Step-by-step explanation:
given equation
x'' + 4x = 0 ; x(0) = 5, x'(0) = 0
L{ x'' + 4 x } = 0
L{x''} + 4 L{x} = 0
s² . L(x) - s . x(0) - x'(0) + 4 L{x} = 0
( s² + 4 ). L(x) - 5 s = 0
L(x) = 
= cos at
so,
x = 5 
x = 5 cos 2t