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Anettt [7]
3 years ago
14

What is the equation of a circle with radius 4 and center (0,8)?

Mathematics
1 answer:
adoni [48]3 years ago
5 0

The equation of circle with the center at (h,k) is:

\large \boxed{ {(x - h)}^{2}  +  {(y - k)}^{2}  =  {r}^{2} }

r stands for radius. Therefore r^2 = diameter or 2×radius.

The question has already given the information we need, which are:

  • radius = 4
  • the center at (0,8)

Since the center is (h,k) - therefore the center is at h = 0 and k = 8 making it (h,k) = (0,8).

Substitute the values in the equation:

\large{ {(x - 0)}^{2}  +  {(y - 8)}^{2}  =  {4}^{2} }

Simplify to the simplest form

\large \boxed{ {x}^{2}  +  {(y - 8)}^{2}  = 16}   \:  \:  \:  \: \huge{ \green{\checkmark}}

Answer

  • The equation of a circle is x^2+(y-8)^2 = 16

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