ANSWER:
Let t = logtan[x/2]
⇒dt = 1/ tan[x/2] * sec² x/2 × ½ dx
⇒dt = 1/2 cos² x/2 × cot x/2dx
⇒dt = 1/2 * 1/ cos² x/2 × cosx/2 / sin x/2 dx
⇒dt = 1/2 cosx/2 / sin x/2 dx
⇒dt = 1/sinxdx
⇒dt = cosecxdx
Putting it in the integration we get,
∫cosecx / log tan(x/2)dx
= ∫dt/t
= log∣t∣+c
= log∣logtan x/2∣+c where t = logtan x/2
I think the answer is a but I’m not for sure
Hello :
| -4-√2i | = √((-4)² +(-√2)²) =√(16+2) =√18 = √(9×2) = √9 × √2 = 3<span>√2.. (answer B)</span>
Slope of a line passing through two given points
= (y2-y1)/(x2-x1)
For m=3, and substituting coordinates,
3=(1-y)/(4-1)
solve for y
1-y=3*3=9
y=1-9=-8
Answer: y=-8
The 68 - 95 - 99.7 rule, gives the basis to solve this question.
It says that for a normal distribution 95% of the results are between the mean minus 2 standard deviations and the mean plus 2 standard deviations.
Here:
mean = 64.5 inches,
standard deviaton = 2.5 inches
mean - 2 standard deviations = 64.5 inches - 5 inches = 59.5 inches
mean + 2 standard deviations = 64.5 inches + 5 inches = 69.5 inches
Then, the answer is that 95% of women range approximately between 59.5 inches and 69.5 inches.
