Answer:
17,20,23,26,29,32,35,
38,41,44,47,50,53,56,59,62,65,68,
71,74,77,80,83,86,89,92,95,98,101
you add 3 :)
Step-by-step explanation:
X⁰ = 240°
y = 8 cm
explanation provided in image shown and the proving of each angle properties are labelled with brackets(meaning they are legitimate so dont worry )
happy learning !
1. 1
2. 55/100
3. 77/103
to find the radius of x^2+y^2-10x+6y+18=0, we must complete the square:
x^2 - 10x + y^2 + 6y = -18
Then:
x^2 - 10x + 5^2 - 5^2 + y^2 + 6y + 9 - 9 = -18
Collecting all three constants on the right-hand side, r^2 = -18 + 25 + 9 = 16
Then r = +sqrt(16) = +4 (answer)
Given:
JK is tangent to a circle with center H
To find:
The length of HK.
Solution:
The image is attached below.
JK = 8 mi, HJ = 15 mi
JK is tangent to a circle.
The tangent is always perpendicular to the radius.
Therefore, m∠J = 90°
Using Pythagoras theorem:
HK² = JK² + HJ²
HK² = 8² + 15²
HK² = 64 + 225
HK² = 289
HK² = 17²
Taking square root on both sides.
HK = 17
The length of HK is 17 mi.