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zhuklara [117]
3 years ago
9

Really need help ?????pls

Mathematics
1 answer:
stealth61 [152]3 years ago
3 0

Answer:

34,833.21 ft³

Step-by-step explanation:

Volume of a cylinder = πr²h

r is the radius

h is the height

Given

height h = 19 3/4 ft

d = 1 1/5h

d = 6/5 * h

d = 6/5 * 19 3/4

d = 6/5 * 79/4

d = 474/20

radius r = 474/20 * 1/2

radius r = 474/40

radus r = 11 34/40

radus r = 11 17/20 ft

Get the volume

V = 3.14 * (474/40)² * 79/4

V = 3.14 * 561.69 * 19.75

V = 34,833.20535

Hence the volume of the cylinder to the nearest hundredth is 34,833.21 ft³

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(b) The power of the test is 0.3487.

Step-by-step explanation:

We are given that a coin is thrown independently 10 times to test the hypothesis that the probability of heads is 0.5 versus the alternative that the probability is not 0.5.

The test rejects the null hypothesis if either 0 or 10 heads are observed.

Let p = <u><em>probability of obtaining head.</em></u>

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Alternate Hypothesis, H_A : p \neq 0.5

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Type I error states the probability of rejecting the null hypothesis given the fact that the null hypothesis is true.

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            P(Type I error) = \alpha

         P(X = 0/H_0 is true) + P(X = 10/H_0 is true) = \alpha

Also, the event of obtaining heads when a coin is thrown 10 times can be considered as a binomial experiment.

So, X ~ Binom(n = 10, p = 0.5)

P(X = 0/H_0 is true) + P(X = 10/H_0 is true) = \alpha

\binom{10}{0}\times 0.5^{0} \times (1-0.5)^{10-0}  +\binom{10}{10}\times 0.5^{10} \times (1-0.5)^{10-10}  = \alpha

(1\times 1\times 0.5^{10})  +(1 \times 0.5^{10} \times 0.5^{0}) = \alpha

\alpha = 0.0019

So, the significance level of the test is 0.002.

(b) It is stated that the probability of heads is 0.1, and we have to find the power of the test.

Here the Type II error is used which states the probability of accepting the null hypothesis given the fact that the null hypothesis is false.

Also, the power of the test is represented by (1 - \beta).

So, here, X ~ Binom(n = 10, p = 0.1)

1-\beta = P(X = 0/H_0 is true) + P(X = 10/H_0 is true)

1-\beta = \binom{10}{0}\times 0.1^{0} \times (1-0.1)^{10-0}  +\binom{10}{10}\times 0.1^{10} \times (1-0.1)^{10-10}  

1-\beta = (1\times 1\times 0.9^{10})  +(1 \times 0.1^{10} \times 0.9^{0})

1-\beta = 0.3487

Hence, the power of the test is 0.3487.

3 0
3 years ago
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