we are given with two dice and that we are asked in the problem to find the probability of the following:
a. sum at least 4b. sum at least 6
THe sample space of this problem is
{11, 12, 13, 14, 15, 16, 21,22, 23,24,25,26,31,32,33,34,35,36,41,42,43,44,45,46,51,52,53,54,55,56,61,62,63,64,65,66} a total of 36.a. 33/36 = 11/12b.11/36
Answer:
<h2>cherry pie = 5</h2><h2>lemon pie =10</h2>
Step-by-step explanation:
Step one:
let cherry be x
and lemon be y
the systems of the equation for the solution is given as
4x+y=30-----------1
8x+6y=100------2
Step two:
solve the equation simultaneously by substitution we have
4x+y=30
y=30-4x
put y=30-4x in equation 2
8x+6(30-4x)=100
8x+180-24x=100
8x-24x=100-180
-16x=-80
x=80/16
x=5
put x=4 in y=30-4x
y=30-4(5).
y=30-20
y=10
Answer:
1 pound of apples costs $1.50; Use that to solve the other problems.
a. 1.50 * 3 = $4.50
b. 6 / 4 = $1.50
c. $1.50 * 40 = 60lbs
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We are required to find the price of the first game
The price of the first game is $20
Given:
let
price of the first game = x
price of the second game = x + 50% of x
= x + 0.5x
= 1.5x
Price of the third game = 50% of 1.5x
= 0.5 × 1.5x
= 0.75x
Total cost of game = $65
<em>Total cost of game = price of the first game + price of the second game + Price of the third game</em>
65 = x + 1.5x + 0.75x
65 = 3.25x
divide both sides by 3.25
x = 65 ÷ 3.25
x = 20
Therefore, the price of the first game is $20
Read more:
brainly.com/question/291220
