Answer: He can predict that 420 students will be in support of the purchase.
Step-by-step explanation:
Since Randy surveyed one student out of every 5 he came across in the cafeteria, it means that if he came across five people, he will survey one, if he came across ten students, he will survey 2 and so on.
If then he surveyed a total of 140 students, then we can actually multiply the number by 5 to know the exact number of students he possibly came across in the cafeteria:
= 140 × 5
= Total of 700 students
If 84 out of the surveyed students supported the purchase, we can find what that figure represents in the total number of students in the cafeteria:
84/140 = x/700
We cross multiply
140 × X = 84 × 700
140X = 58,800
X = 58,800/140
X = 420 students
Therefore, he can predict that 420 students out of a total of 700 students in the cafeteria will be in support of the purchase of the P.E equipment
Answer:
The Total number of peoples went to street fair including all three days is 785 peoples .
Step-by-step explanation:
Given as :
The number of people went to fair on Friday = F = 215 peoples
The number of people went to fair on Saturday = Sa = 163 more people than on Friday
So, The number of people went to fair on Saturday = The number of people went to fair on Friday + 163 peoples
∴, The number of people went to fair on Saturday = 215 + 163 = 378 peoples
And
The number of people went to fair on Sunday = Su = 192 peoples
So , The Total number of peoples went to fair = The number of people went to fair on Friday + The number of people went to fair on Saturday + The number of people went to fair on Sunday
So, The Total number of peoples went to fair = 215 peoples + 378 peoples + 192 peoples
∴ The Total number of peoples went to fair = 785 peoples
Hence , The Total number of peoples went to street fair including all three days is 785 peoples . Answer
Answer:
Option B. 8 mi, 9 mi, 2 mi
Step-by-step explanation:
The option A doesn't have a set of numbers which could be the lengths of the sides of a triangle. The numbers 1,9,10 mean that the longest side is exactly the sum of the others. The only possible way is they lie in the same line, no triangle is formed
Option C gives the numbers 1,9,11. It's impossible to have a side of 11 when you have the sum of the others less than 11. The maximum extension of the other sides (forming a line) won't be enough to reach the length of 11
Option D is also infeasible for the same reason as the option A. The three lines must be aligned to be connected in its extremes
Option B is the only one who can provide a set of possible lengths of a triangle since the sum of the shortest sides is greater than the third. If we open wide enough the angle between the 2 mi side and the 8 mi side, we would eventually connect the 9 mi side and form a triangle
#3 describes an isosceles triangle.
#5 describes an equilateral triangle.
#7 describes a right triangle.
Answer:
Following are the solution to the given question:
Step-by-step explanation:
The population std. dev of the dog weight=8
Calculating the payout w s.t:
![E[netpay]=0=(-5) \times 0.9544+w\times (1-0.9544)\\\\ w =(5 \times \frac{0.9544}{1-0.9544}) =\$ 104.65](https://tex.z-dn.net/?f=E%5Bnetpay%5D%3D0%3D%28-5%29%20%5Ctimes%200.9544%2Bw%5Ctimes%20%281-0.9544%29%5C%5C%5C%5C%20w%20%3D%285%20%5Ctimes%20%5Cfrac%7B0.9544%7D%7B1-0.9544%7D%29%20%3D%5C%24%20104.65)
therefore, we assume that the weight of the dog is a normal distribution with std. deviation that is 8.
