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3 years ago

The function f(x)=(2x-3)(x+k).Given that f(0)=15. Calculate

Mathematics

1 answer:

Valentin [98]3 years ago

4 0

Answer:

(a-b)

Step-by-step explanation:

a minus b whole square minus C square

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What is the multiplicative rate of change of the function

mario62 [17]

Answer: B $\frac{2}{3}$

Step-by-step explanation:

From the given table

When x changes from 1 to 2 , value of y changes from 6 to 4

The multiplicative rate of change= $\frac{4}{6}=\frac{2}{3}$

Similarly we can check

When x changes from 2 to 3 , value of y changes from 4 to $\frac{8}{3}$

The multiplicative rate of change= $\frac{\frac{8}{3}}{4}=\frac{2}{3}$

When x changes from 3 to 4 , value of y changes from $\frac{8}{3}$ to $\frac{16}{9}$

The multiplicative rate of change= $\frac{\frac{16}{9}}{\frac{8}{3}}=\frac{2}{3}$

Therefore, the multiplicative rate of exponential function = $\frac{2}{3}$

5 0

3 years ago

Read 2 more answers

If q is the midpoint of segment PR, find the coordinates of R if P (11,-2) and Q (4,3)

Murrr4er [49]

Answer:

R(-3, 8)

Step-by-step explanation:

R = 2Q -P

R = 2(4, 3) -(11, -2) = (8-11, 6+2)

R = (-3, 8)

_____

You can derive the formula for the endpoint from the formula for the midpoint:

Q = (R + P)/2

R = 2Q - P . . . . . . multiply by 2 and subtract P

3 0

3 years ago

The expressions 10/12(245b−365) and 2/3(3b+6) represent the lengths of the diagonals of parallelogram WXYZ. For what value of b

makkiz [27]

Answer:

b = 1.52

Step-by-step explanation:

Length of diagonals of a parallelogram = $\frac{10}{12}(245b - 365)$ and $\frac{2}{3}(3b+6)$

If the given parallelogram is a rectangle,

Length of the diagonals will be equal in measure,

Therefore, $\frac{10}{12}(245b - 365)=\frac{2}{3}(3b+6)$

245b - 365 = $\frac{12}{10}\times \frac{2}{3}(3b+6)$

245b - 365 = $\frac{4}{5}(3b+6)$

5(245b - 365) = 4(3b + 6)

1225b - 1825 = 12b + 24

1225b - 12b = 24 + 1825

1213b = 1849

b = $\frac{1849}{1213}$

b = 1.52

5 0

3 years ago

How much more interest will Maria receive if she invests $1,000 for one year at x percent annual interest, compounded semiannual

notka56 [123]

Answer:

$0.025x² . . . where x is a number of percentage points

Step-by-step explanation:

The multiplier for semi-annual compounding will be ...

(1 + x/2)² = 1 + x + x²/4

The multiplier for annual compounding will be ...

1 + x

The multiplier for semiannual compounding is greater by ...

(1 + x + x²/4) - (1 + x) = x²/4

Maria's interest will be greater by $1000×(x²/4) = $250x², where x is a decimal fraction.

If x is a percent value, as in x = 6 when x percent = 6%, then the difference amount is ...

$250·(x/100)² = $0.025x² . . . where x is a number of percentage points

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<u>Example</u>:

For x percent = 6%, the difference in interest earned on $1000 for one year is $0.025×6² = $0.90.

3 0

3 years ago

One of the following functions is growing at the same rate as 4²

mina [271]

I’m gorilla da spinna RANGABANGIN ON MY CHEST

5 0

3 years ago