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Gennadij [26K]
3 years ago
5

Prime numbers have

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
7 0
The answer is c. Prime number is a number that is only divisible by 1 and it self.
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If anyone could help also step by step please with work
Rasek [7]

9514 1404 393

Answer:

  m = 1/3

Step-by-step explanation:

<u>Step 1</u>. Pick a line of the table to use as (x1, y1).

<u>Step 2</u>. Pick a different line of the table to use as (x2, y2).

<u>Step 3</u>. Use the slope formula:

  m = (y2 -y1)/(x2 -x1)

<u>Step 4</u>. Simplify the result.

__

Here are these steps for this problem.

1, 2. use (x1, y1) = (-9, -5) and (x2, y2) = (-3, -3)

3. m = (-3 -(-5))/(-3 -(-9)) = 2/6

4. m = 1/3

6 0
3 years ago
Height of Dutch Men. Males in the Netherlands are the tallest, on average, in the world with an average height of 183 centimeter
trapecia [35]

Answer:

a) P(X

P(z

b) P(X>195) =P(Z>\frac{195-183}{10.5})=P(Z>1.143)

P(z>1.143)=1-P(Z

c) P(173

P(-0.953

P(-0.953

d) P(\bar X >190)=P(Z>\frac{190-183}{\frac{10.5}{\sqrt{1000}}}=21.08)

And using a calculator, excel ir the normal standard table we have that:

P(Z>21.08)=1-P(Z

So for this case we expect anyone with a heigth higher than 190 cm in a random sample of 1000.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(183,10.5)  

Where \mu=183 and \sigma=10.5

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability with the normal standard table or with excel:

P(z

Part b

P(X>195)

P(X>195) =P(Z>\frac{195-183}{10.5})=P(Z>1.143)

And we can find this probability with the normal standard table or with excel: using the complement rule

P(z>1.143)=1-P(Z

Part c

P(173

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(173And we can find this probability on this way:

P(-0.953

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-0.953Part d

Since the distributiion for X is normal then the distribution for the sample mean is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we eant this probability:

P(\bar X >190)=P(Z>\frac{190-183}{\frac{10.5}{\sqrt{1000}}}=21.08)

And using a calculator, excel ir the normal standard table we have that:

P(Z>21.08)=1-P(Z

So for this case we expect anyone with a heigth higher than 190 cm in a random sample of 1000.

3 0
3 years ago
Can you please help me thank you so much
77julia77 [94]

Answer:

I would say angle 6 is supplementary to angle 3.

Step-by-step explanation:

Supplementary angles are angles that add up to 180 degrees.

Angles 6 and 3 are right angles.

90 + 90 = 180

Hope I helped!

8 0
3 years ago
Read 2 more answers
Evacuate 9-b when b-8
MakcuM [25]

9-b when b=8

9 -8 =1


9-b when b=-8

9 - (-8)

9+8

17


I'm  not sure whether you meant b=8 or b=-8

4 0
3 years ago
Based on the audio, what is an activity Carlos doesn't do every morning?
GREYUIT [131]
Do ph and probably cheat
6 0
3 years ago
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