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ANTONII [103]
2 years ago
6

Solve for y.18y -6 = -30

Mathematics
1 answer:
Marianna [84]2 years ago
4 0
18y-6 = -30
     +6     +6

18y= -24
( divide by 18)
y= -24/18 which can simplify to -4/3
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A triangle with the sides 6,8 and 10 . what kind of triangle is it ?
Taya2010 [7]
It would be right-angled Triangle.

You can check for that, by putting the values into Pythagoras Theorem:
H² = P² + B²
10² = 8² + 6²
100 = 64 + 36
100 = 100
L.H.S = R.H.S

As it obeys Pythagoras theorem, It would be a right-angled triangle only, with two small arms (Base  & Perpendicular) and a long arm, opposite to perpendicular (Hypotenuse)!!!

Hope it helped.

6 0
2 years ago
Read 2 more answers
Damon's father pays him one dollar to start the work and doubles his pay for each hour of work write a function that models the
lidiya [134]

Answer: a

Step-by-step expla

4 0
3 years ago
A population of values has a normal distribution with μ=204.9μ=204.9 and σ=81.9σ=81.9. You intend to draw a random sample of siz
marin [14]

Answer:

7. μ=204.9 and σ=5.4968

8. μ=75.9 and σ=0.7136

9. p=0.9452

Step-by-step explanation:

7. - Given that the population mean =204.9 and the standard deviation is 81.90 and the sample size n=222.

-The sample mean,\mu_xis calculated as:

\mu_x=\mu=204.9, \mu_x=sample \ mean

-The standard deviation,\sigma_x is calculated as:

\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{81.9}{\sqrt{222}}\\\\=5.4968

8. For a random variable X.

-Given a X's population mean is 75.9, standard deviation is 9.6 and a sample size of 181

-#The sample mean,\mu_x is calculated as:

\mu_x=\mu\\\\=75.9

#The sample standard deviation is calculated as follows:

\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{9.6}{\sqrt{181}}\\\\=0.7136

9. Given the population mean, μ=135.7 and σ=88 and n=59

#We calculate the sample mean;

\mu_x=\mu=135.7

#Sample standard deviation:

\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{88}{\sqrt{59}}\\\\=11.4566

#The sample size, n=59 is at least 30, so we apply Central Limit Theorem:

P(\bar X>117.4)=P(Z>\frac{117.4-\mu_{\bar x}}{\sigma_x})\\\\=P(Z>\frac{117.4-135.7}{11.4566})\\\\=P(Z>-1.5973)\\\\=1-0.05480 \\\\=0.9452

Hence, the probability of a random sample's mean being greater than 117.4 is 0.9452

7 0
3 years ago
Sandy spun a spinner with 5 equal parts labeled 1-5. If she spins the spinner 20 times, how many times should she expect to spin
MatroZZZ [7]

Answer:

probably 4 times since it is not 100% accurate I guess

4 0
2 years ago
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LekaFEV [45]
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Since you can leave x negative you reverse it with 1 and your answer will be >>> x = -1
6 0
3 years ago
Read 2 more answers
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