Boi. This is the easiest question i've ever answered. The line that crosses the y-axis at the point (0,-1) (the line on the right)
Answer:
y" = csc(x)[9cot²(x) - csc²(x)]
Step-by-step explanation:
Step 1: Define
y = 9csc(x)
Step 2: Find 1st derivative
y' = -9csc(x)cot(x)
Step 3: Find 2nd derivative
y" = 9csc(x)cot(x)cot(x) + -csc(x)csc²(x)
y" = 9csc(x)cot²(x) - csc³(x)
y" = csc(x)[9cot²(x) - csc²(x)]
Answer:428 7/100
Step-by-step explanation:
Answer:
y = 4x + 1
Step-by-step explanation:
y = mx + b
b = y-intercept
From the graph we see that b = 1
m = slope
Start at (0, 1). Go up 8 units. Rise = 8. Go right 2 units. Run = 2.
slope = rise/run = 8/2 = 4
y = 4x + 1
