The Given Triangle PMO is a Right Angled Triangle with m∠M = 90°
Given m∠P = 40°
We know that : Sum of Angles in a Triangle = 180°
⇒ m∠P + m∠M + m∠O = 180°
⇒ 40° + 90° + m∠O = 180°
⇒ 130° + m∠O = 180°
⇒ m∠O = 180° - 130°
⇒ m∠O = 50°
We can notice that m∠O and m∠1 form a Linear Pair (180°)
⇒ m∠O + m∠1 = 180°
⇒ 50° + m∠1 = 180°
⇒ m∠1 = 180° - 50°
⇒ m∠1 = 130°
Last Option is the Answer
Answer is quantom physics cant equate to the sum of the x
Answer:
D
Step-by-step explanation:
If y = log x is the basic function, let's see the transformation rule(s):
Then,
1. y = log (x-a) is the original shifted a units to the right.
2. y = log x + b is the original shifted b units up
Hence, from the equation, we can say that this graph is:
** 2 units shifted right (with respect to original), and
** 10 units shifted up (with respect to original)
<u><em>only, left or right shift affects vertical asymptotes.</em></u>
Since, the graph of y = log x has x = 0 as the vertical asymptote and the transformed graph is shifted 2 units right (to x = 2), x = 2 is the new vertical asymptote.
Answer choice D is right.
6x + 7(1-x) = -4(x-4)
6x + 7 - 7x = -4x + 16
-x + 7 = -4x + 16
-x + 4x = 16 - 7
3x = 9
x =9/3
x = 3
