All you do is multiply 2 by 10 to the power of -6. 2*10^(-6)
Answer:
an = 17n - 46
a50 = 804
Step-by-step explanation:
-29, -12, 5, 22, ...
Subtract each number from the next one.
-12 - (-29) = 17
5 - (-12) = 17
22 - 5 = 17
The common difference is 17. This is an arithmetic sequence which starts with -29, and in which each subsequent value is 17 more than the previous value.
a1 = -29
a2 = -29 + 17
a3 = -29 + 2(17)
a4 = -29 + 3(17)
Notice that for each term, you have -29 and something added to it. What you add to -29 is 17 multiplied by 1 less than the number of the term. For term 1, 1 less than 1 is 0. You add 0 * 17 to -29 and get -29. term 1 is -29. For term 2, 1 less than 2 is 1. You add 1 * 17 to -29 and get -12, etc.
For term n, 1 less than n is n - 1. Add (n - 1) * 17 to -29 to get term n.
an = -29 + 17(n - 1)
This formula can be simplified.
an = -29 + 17n - 17
an = -46 + 17n
an = 17n - 46
a50 = 17(50) - 46
a50 = 804
Answer:
Option D. 8
Step-by-step explanation:
we have
Remember that
substitute
Remove the discontinuity at x=4
Simplify
so
Find the value of f(4)
For x=4
I= Ishaan's age= 2C
C= Christopher's age
35 years ago means we have to subtract 35 from their current age. Ishaan minus 35 equals 7 times Christopher minus 35 years.
CHRISTOPHER'S AGE:
I - 35= 7(C-35)
substitute I=2C in for I
multiply 7 by all in parenthesis
2C - 35= 7C - 245
add 35 to both sides
2C= 7C - 210
subtract 7C from both sides
-5C = -210
divide both sides by -5
C= 42 Christopher's age
ISHAAN'S AGE:
I= 2C
substitute C=42 to find Ishaan's age
I= 2(42)
I= 84 Ishaan's age
CHECK:
Substitute answers in original equation
I - 35= 7(C-35)
84 - 35= 7(42-35)
49= (7*42)+(7*-35)
49= 294-245
49=49
Hope this helps! :)
