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3 years ago

What is the range of these numbers 10, 12, 8, 11, 10, 15, 7

Mathematics

1 answer:

NARA [144]3 years ago

4 0

Answer:

Step-by-step explanation:

Range of a certain set of numbers is the largest number - smallest number

=> 15 - 7

=> 8

Hope it helps :)

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The lines (m-2)x+y=2 and mx+2y=k intersect at (2,8). Find the values of m and k

Lerok [7]

Step-by-step explanation:

(m - 2)x + y = 2

y = -(m - 2)x + 2

8 = -(m - 2)(2) + 2

6 = -(m - 2)(2)

3 = -(m - 2)

-3 = m - 2

-1 = m

mx + 2y = k

2y = -mx + k

$y = - \frac{1}{2} mx + \frac{k}{2} \\ y = \frac{1}{2} x + \frac{k}{2} \\ 8 = \frac{1}{2} (2) + \frac{k}{2} \\ 7 = \frac{k}{2} \\ 14 = k$

4 0

3 years ago

What is a simpler form of the expression? (2n 2 + 5n + 3)(4n – 5) A. 8n 3 + 10n 2 – 13n – 15 B. 8n 3 + 30n 2 – 37n – 15 C. 8n 3

Sonja [21]

<span>(2n^2 + 5n + 3)(4n – 5)
= 8n^3 -10n^2 + 20n^2 - 25n + 12n - 15
= 8n^3 + 10n^2 - 13n - 15

answer is </span><span>A. 8n^3 + 10n^2 – 13n – 15

hope that helps</span>

3 0

3 years ago

Nikola works as an electrician and is paid $22.50 an hour. Over the course of a month he works 40 hours a week, and this month t

Oduvanchick [21]

Answer:

$3600

Step-by-step explanation:

7 0

4 years ago

In a box of 10 calculators, one is defective. In how many ways can four calculators be selected, if you know one

Juliette [100K]

Given:

Total number of calculators in a box = 10

Defective calculators in the box = 1

To find:

The number of ways in which four calculators be selected and one of the four calculator is defective.

Solution:

We have,

Total calculators = 10

Defective calculators = 1

Then, Non-defective calculator = 10-1 = 9

Out of 4 selected calculators 1 should be defective. So, 3 calculators are selected from 9 non-defective calculators and 1 is selected from the defective calculator.

$\text{Total ways}=^9C_3\times ^1C_1$

$\text{Total ways}=\dfrac{9!}{3!(9-3)!}\times 1$

$\text{Total ways}=\dfrac{9\times 8\times 7\times 6!}{3\times 2\times 1\times 6!}$

$\text{Total ways}=\dfrac{9\times 8\times 7}{6}$

$\text{Total ways}=3\times 4\times 7$

$\text{Total ways}=84$

Therefore, the four calculators can be selected in 84 ways.

7 0

3 years ago

Find the distance between the two points rounding to the nearest tenth (if necessary).

Vaselesa [24]

Hey there! I'm happy to help!

Imagine the line that is created when you connect the two points (the distance between the two points).

You can create a right triangle where this distance is the hypotenuse where the two legs are the change in x and y. So, if you take those changes in x and y, you can use the Pythagorean Theorem (a²+b²=c²) to find the distance between the two points, which is the hypotenuse.

Our change in x is 9 because 9-0 is 9.

We square it

9²=81

Our change in y is 5 as -1-(-6) or -1+6 is 5.

5²=25

We add these.

81+25=106

We square root and round to the nearest tenth.

√106≈10.3

So, our distance is 10.3.

This Pythagorean Theorem method actually gives us a formula called the distance formula that you can use to find the distance between points.

$\sqrt{(x_{2} -x_{1})^2+(y_{2}-y_{1})^2}$

Have a wonderful day and keep on learning! :D

8 0

3 years ago