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3 years ago

Find the domain of fg f(x)=x+2 g(x)=1/x+2

Mathematics

1 answer:

anygoal [31]3 years ago

6 0

Answer: A. All real numbers

Step-by-step explanation:

Find fg;

f(x) * g(x) = (x + 2) * ( 1 / x + 2)

= ( x + 2) / (x + 2)

= 1

In giving 1 as the product, the domain of fg is any real number.

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If the sales tax rate is 7.6%, how much sales tax will you pay on a $330 item?

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If the sales tax rate is 7.6%, how much sales tax will you pay on a $330 item?

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(05.05)On a coordinate plane, the coordinates of vertices R and T for a polygon are R(−6, 2) and T(1, 2). What is the length of

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The length of Side RT of the polygon is $7\ units$

Step-by-step explanation:

we know that

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what is the general form of the equation of a circle with its Center at -2 1 and passing through -4 one

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Answer:

$\large\boxed{x^2+y^2+4x-2y+1=0}$

Step-by-step explanation:

The standard form of an equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

The general form of an equation of a circle:

$x^2+y^2+Dx+Ey+F=0$

We have the center (-2, 1). Substitute to the equation in the standard form:

$(x-(-2))^2+(y-1)^2=r^2\\\\(x+2)^2+(y-1)^2=r^2$

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$(-4+2)^2+(1-1)^2=r^2\\\\r^2=(-2)^2+0^2\\\\r^2=4$

Therefore we have the equation:

$(x+2)^2+(y-1)^2=4$

Convert to the general form.

Use $(a\pm b)^2=a^2\pm 2ab+b^2$

$(x+2)^2+(y-1)^2=4\\\\x^2+2(x)(2)+2^2+y^2-2(y)(1)+1^2=4\\\\x^2+4x+4+y^2-2y+1=4\qquad\text{subtract 4 from both sides}\\\\x^2+y^2+4x-2y+1=0$

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