Answer:
12.1 seconds
Explanation:
Step 1:
Assuming the following data :
N: Size of packet = 30 Mb
T: Transmission rate = 10 Mbps
C: Speed of light in copper = 2 * 10^8 m/s
L: Length of link 5000 km
Step 2:
Calculation of the Transmission delay and the Propagation Delay
Transmission delay =
=
= 3s
Propagation delay =
=
= 0.025s
Step 3:
Calculation of the end-to -end delay
The end-to-end delay = 4*(Transmission Delay+Propagation Delay) = 4*(3+0.025) = 12.1 seconds
Answer:
The code commented is given below, also the lines that start with # are comments that explains the code.
# Create a function named times_print that receives 2 values x and y
def times_print(x, y):
# Print the formatted string
print("The value of {} times {} is {}".format(x,y,x*y))
# Create the main function
def main():
# Call the funciton times_print 3 times with different values
times_print(2,3)
times_print(4,5)
times_print(5,6)
# Execute the main function
main()
Explanation:
The code was written using Python 3.5, and here I attach the screenshots of the program running:
Answer:
it would be Animation I declare
For an agile team, Six Sigma would provide them with a structured approach for empirical problem solving.