Answer:
You will need to implement a for loop ( I am assuming this is java)
Explanation:
int count20s = 0;
for(int x =0; x< customerAges.length;x++){
if(20 <= customerAges[x] && customerAges[x] <= 29){
count20s++;
}
open intersection is one without traffic control signs or signals. When you enter one, you must yield the right-of-way if: A vehicle is already in the intersection. You enter or cross a state highway from a secondary road. hope this helped
How efficient well if we are transmitting 6bits and we need 10 to transmit the 6 bits that would be 6/10 = .6 = 60% efficient.
Answer:
Following are statement is given below
int k=1,total=0; // variable declaration
while(k<50) // iterating the while loop
{
total=total+k*k;// calculating the square
k=k+1; // increments the value of k by 1
}
Explanation:
Following are the description of Statement.
- Declared a variable "total" and "k" of the "integer " type initialized the total to 0 and "k" to 1.
- Iterating the while loop for less then 50 .In this loop, we calculating the sum of square of first 50 number in the "total" variable .
- After that increment the value of "k" variable by 1 to execute the loop less then 50 .
