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olga55 [171]
2 years ago
10

Question is: Solve -7(x+6)=4(x+6)

Mathematics
2 answers:
Alina [70]2 years ago
8 0

\huge\boxed{x=-6}

Hey there! Our goal here is to isolate the variable on one side of the equation.

\begin{aligned}-7(x+6)&=4(x+6)&&\smash{\Big|}&&\textsf{Start with the original equation.}\\-7x+(-7)(6)&=4x+4(6)&&\smash{\Big|}&&\textsf{Distribute.}\\-7x-42&=4x+24&&\smash{\Big|}&&\textsf{Multiply.}\\-7x-4x&=24+42&&\smash{\Big|}&&\textsf{Move the terms.}\\-11x&=66&&\smash{\Big|}&&\textsf{Combine like terms.}\\x&=\boxed{-6}&&\smash{\Big|}&&\textsf{Divide both sides by $-11$.}\end{aligned}

xxTIMURxx [149]2 years ago
5 0

Answer: The answer is x=–6.

Step-by-step explanation: Step 1: Simplify both sides of the equation:

(-7)(x)+(-7)(6)=(4)(x)+(4 )(6) (Distributive Property)

-7x+-42=4x+24

-7x-42=4x+24

Step 2: Subtract 4x by the both sides: -7x-42-4x=4x+24-4x

-11x-42=24

Step 3: Add 42 to the both sides: -11x-42+42=24+42

-11x=66

And step 4: Divide both sides by -11: \frac{-11x}{-11}=\frac{66}{-11}, x=-6.

I hoped this formula step-by-step is very helpful, please mark me as brainliest, and have a happy holidays! :D

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Answer:

See Explanation

Step-by-step explanation:

<em>Question like this are better answered if there are list of options; However, I'll simplify as far as the expression can be simplified</em>

Given

sec^4 x + sec^2 x tan^2 x - 2 tan^4 x

Required

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Substitute 1 for sec^2x - tan^2x in (sec^2x -tan^2x) (sec^2x+ 2 tan^2x)

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In trigonometry

secx = \frac{1}{cosx}

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Substitute the expressions for secx and tanx

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(secx)^2+ 2 (tanx)^2 becomes

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Make sin^2x the subject of formula

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Open bracket

\frac{1 + 2  - 2cos^2x}{cos^2x}

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