Twenty-one thousand and sixty-three divided by three is 7021
First, take any number (for this example it will be 492) and add together each digit in the number (4+9+2 = 15). Then take that sum (15) and determine if it is divisible by 3. The original number is divisible by 3 (or 9) if and only if the sum of its digits is divisible by 3 (or 9).If a number is a multiplication of 3 consecutive numbers then that number is always divisible by 3. This is useful for when the number takes the form of (n * (n - 1)*(n + 1))Example: 492 (The original number). 4 + 9 + 2 = 15 (Add each individual digit together). 15 is divisible by 3 at which point we can stop. Alternatively we can continue using the same method if the number is still too large: 1 + 5 = 6 (Add each individual digit together). 6 ÷ 3 = 2 (Check to see if the number received is divisible by 3). 492 ÷ 3 = 164 (If the number obtained by using the rule is divisible by 3, then the whole number is divisible by 3)
Given that:
(x+2)(2x-5)=54
We have:
Using the quadratic formula, this is approximately 5.66, so rounded to the nearest whole number, our answer is 6.
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Answer: Choice B. f(x) = 100 - 68x</h3>
Work Shown:
Solve for y. Then replace y with f(x).
Effectively this involves adding 1000 to both sides and subtracting 680x from both sides, afterward we divide both sides by 10 to isolate y.
I think 12 might be the second one, I'm not sure though!
Remainder theorem again...
So Yes, is a factor.