Answer:
24 candies originally
Step-by-step explanation:
Add the 4 to how many you had left, then think about that number, 16, and what goes into 16 evenly 2 times? 8 and originally she gave away 1/3 of the box and if you were to add another 8 to the box it would be 24 divided by 1/3, -,-4,= 12.
Assume that the rule connecting height of the candle to time is a linear one. If you do, then we have to find the equation of this line, and then use this equation to predict the height of the candle after 11 hours.
Two points on this line are (6,17.4) and (23, 7.2). The slope is thus
7.2-17.4 -6
m = --------------- = ----------- or -3/5.
23-6 10
Find the equation of the line. I'm going to use the slope-intercept formula:
y = mx + b => 7.2 = (-3/5)(23) + b. Solving for b, b = 21.
Now we know that y = (-3/5)x + 21
Let x=11 to predict the height of the candle at that time.
y = (-3/5)(11) + 21 = 14.4 inches (answer)
9514 1404 393
Answer:
A. 18
Step-by-step explanation:
The area of a trapezoid is given by the formula ...
A = 1/2(b1 +b2)h
Here, the parallel bases have lengths 3 and 9. The height is 3, so the area is ...
A = 1/2(3 +9)(3) = 18
The area of the trapezoid is 18 square units.
Answer: The required product is ![10x^2-y^2+3xy+6x+3y.](https://tex.z-dn.net/?f=10x%5E2-y%5E2%2B3xy%2B6x%2B3y.)
Step-by-step explanation: We are to find the product f the following two algebraic expressions:
![E_1=2x+y,\\\\E_2=5x-y+3.](https://tex.z-dn.net/?f=E_1%3D2x%2By%2C%5C%5C%5C%5CE_2%3D5x-y%2B3.)
To find the product of the above two expressions, we must multiply each term of the first expression with each term of the second expression.
The multiplication is as follows:
![M\\\\=E_1 \times E_2\\\\=(2x+y)\times(5x-y+3)\\\\=10x^2-2xy+6x+5xy-y^2+3y\\\\=10x^2-y^2+3xy+6x+3y.](https://tex.z-dn.net/?f=M%5C%5C%5C%5C%3DE_1%20%5Ctimes%20E_2%5C%5C%5C%5C%3D%282x%2By%29%5Ctimes%285x-y%2B3%29%5C%5C%5C%5C%3D10x%5E2-2xy%2B6x%2B5xy-y%5E2%2B3y%5C%5C%5C%5C%3D10x%5E2-y%5E2%2B3xy%2B6x%2B3y.)
Thus, the required product is ![10x^2-y^2+3xy+6x+3y.](https://tex.z-dn.net/?f=10x%5E2-y%5E2%2B3xy%2B6x%2B3y.)