All categories

3 years ago

Solve V=1/3bh for b base of the cone

Mathematics

1 answer:

Wittaler [7]3 years ago

8 0

Answer:

V = 1/3 * b * h...divide both sides by 1/3h

V / (1/3h) = b

3V/h = b

Step-by-step explanation:

You might be interested in

Please HELP! Which figure is a regular convex polygon?

sergij07 [2.7K]

That would be figure D.

3 0

3 years ago

Which of the following is not a congruence transformation?

VladimirAG [237]

$\bold{Heya!}$

Your answer to this is :

<h2>C. Stretching.</h2>

<h2>→ <u>Explanation:-</u></h2>

<u />

Because the other one is congruent together.

Hopefully This Helps ! ~

#LearnWithBrainly

$\underline{Answer :}$

<em>Jaceysan ~</em>

5 0

2 years ago

Read 2 more answers

What is the slope of a linear that is perpendicular to the line y=-1/2x+5?

Vlada [557]

Step-by-step explanation:

Equation of given line is:

$y = - \frac{1}{2} x + 5 \\ \\ equating \: it \: with \: y =m_1x + c \\ we \: find \: \\ m_1 = - \frac{1}{2} \\ let \: m_2 \: be \: the \: slope \: of \: required \: line \\ \\ \therefore \: m_1 \times m_2 = - 1( \because \: lines \: are \: \perp) \\ \\ \therefore \: - \frac{1}{2} \times m_2 = - 1\\ \\ \therefore \: m_2 = 2 \\$

Thus, the slope of required line is 2.

6 0

3 years ago

What is the zero of function f?f(x)=3 square root of x+3 -6

grin007 [14]

Solution:

Given:

$f(x)=3\sqrt{x+3}-6$

The zeros of a function are the values of x when f(x) is equal to 0.

Hence,

$\begin{gathered} 0=3\sqrt{x+3}-6 \\ \\ Collecting\text{ the like terms,} \\ 0+6=3\sqrt{x+3} \\ 6=3\sqrt{x+3} \\ \\ Divide\text{ both sides by 3;} \\ \frac{6}{3}=\sqrt{x+3} \\ 2=\sqrt{x+3} \\ \\ Taking\text{ the square of both sides;} \\ 2^2=x+3 \\ 4=x+3 \\ \\ Collecting\text{ the like terms;} \\ 4-3=x \\ 1=x \\ x=1 \end{gathered}$

Therefore, x = 1

The correct answer is OPTION A.

3 0

1 year ago

How to do this? (#21 and #23)

Readme [11.4K]

Answer:

$\large\boxed{21.\ g(x)=f(x-2)+1\to g(x)=\log_3(x-2)+1}\\\\\boxed{22.\ g(x)=f(x)-4\to g(x)=3^x-4}\\\\\boxed{23.\ g(x)=-f(x)\to g(x)=-\log_{\frac{1}{2}}x}$