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3 years ago

Solve V=1/3bh for b base of the cone

Mathematics

1 answer:

Wittaler [7]3 years ago

8 0

Answer:

V = 1/3 * b * h...divide both sides by 1/3h

V / (1/3h) = b

3V/h = b

Step-by-step explanation:

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Simplify completely. 5(x - 2) + 2x

fomenos

<span>5(x - 2) + 2x
= 5x - 10 + 2x
= 7x -10

answer
</span>7x -10

4 0

3 years ago

Read 2 more answers

(x+5)(X + 11)<br> please help

dexar [7]

Answer:

$\left(x+5\right)\left(x+11\right)\\\\=xx+x\cdot \:11+5x+5\cdot \:11\\\\=xx+11x+5x+5\cdot \:11\\\\=x^2+16x+55$

hope this helps you

3 0

2 years ago

Please help ASAP!! WILL MARK BRAINLY!!

erastova [34]

Answer:

$A=91^o$

$B=146^o$

$C=89^o$

$D=34^o$

Step-by-step explanation:

we know that

In an inscribed quadrilateral ABCD opposite angles are supplementary

$A+C=180^o$ ----> equation 1

$B+D=180^o$ ----> equation 2

step 1

Find the value of x

substitute the given values in equation 1

$(2x+3)^o+(2x+1)^o=180^o$

$4x=180-4\\4x=176\\x=44$

step 2

Find the measure of angle A,C and D

substitute the value of x

$A=(2(44)+3)=91^o$

$C=(2(44)+1)=89^o$

$D=(44-10)=34^o$

step 3

Find the measure of angle B

Remember the equation 2

$B+D=180^o$ ----> equation 2

substitute the value of D

$B+34^o=180^o$

$B=180^o-34^o=146^o$

6 0

3 years ago

Factorise<br>3ab + 3a + 2b + 2

marin [14]

Answer:

3ab + 3a + 2b + 2

3a(b+1)+2(b+1)

(b+1)(3a+2)

3 0

2 years ago

If jl= 10x-2 JK = 5x-8 and KL = 7x-12 find KL

natta225 [31]

JK+KL=JL
(5x-8)+7x-12=10x-2
(add common terms together)
12x-20=10x-2
(get the term with x alone on one side of the equation)
2x=18
(divide by 2 to get x alone)
x=9

Find KL:
KL=7(9)-12
KL=51

8 0

3 years ago