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3 years ago

Solve the system of equations 5x+3y=5 5x+7y=25

Mathematics

1 answer:

irinina [24]3 years ago

6 0

Answer:

(-2,5)

Step-by-step explanation:

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Which expression can be used to find the volume of the sphere?

Kryger [21]

Answer:

They used 3.14 for pi:

$V=\frac{4}{3} \pi r^3$

$V=\frac{4}{3} (3.14)(5)^3$

Step-by-step explanation:

$V=\frac{4}{3}\pi r^3$ is the volume of a sphere with radius r.

I think that is the diameter given in the picture.

The radius is half the diameter.

So the radius is 5 since the diameter is 10.

Plug in this gives you:

$V=\frac{4}{3} \pi (5)^3$

4 0

3 years ago

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Explain what mistake was made in the problem below and what should be the

romanna [79]

Answer:

Instead of moving the 3x to the opposite side of the equation they moved the 2x. And the correct answer is x=-6 not x=6.

Step-by-step explanation:

Student Work:

2(x + 4) – 8 = 3x+10-4

2x + 8–8 = 3x + 6

2x = 3x + 6

- 3x – 3x

X = 6

My work:

2(x+4)-8=3x+10-4

2x+8-8=3x+6

2x=3x+6

-x=6

x=-6

7 0

4 years ago

What does y equal??????

tangare [24]

Answer:

118 degrees

Step-by-step explanation:

I think you it's the same, because it a just rotation of the shape.

5 0

3 years ago

Read 2 more answers

A playground is being designed where children can interact with their friends in certain combinations. If there is 1 child, ther

mariarad [96]

<h2>Answer:</h2>

Recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

<h2>Step-by-step explanation:</h2>

In the question,

The number of interaction for 1 child = 0

Number of interactions for 2 children = 1

Number of interactions for 3 children = 5

Number of interaction for 4 children = 14

So,

We need to find out the pattern for the recursive equation for the given conditions.

So,

We see that,

$a_{1}=0\\a_{2}=1\\a_{3}=5\\a_{4}=14\\$

Therefore, on checking, we observe that,

$a_{n}=a_{n-1}+(n-1)^{2}$

On checking the equation at the given values of 'n' of, 1, 2, 3 and 4.

At,

n = 1

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{1}=a_{1-1}+(1-1)^{2}\\a_{1}=0+0=0\\a_{1}=0$

which is true.

At,

n = 2

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{2}=a_{2-1}+(2-1)^{2}\\a_{2}=a_{1}+1\\a_{2}=1$

Which is also true.

At,

n = 3

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{3}=a_{3-1}+(3-1)^{2}\\a_{3}=a_{2}+4\\a_{3}=5$

Which is true.

At,

n = 4

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{4}=a_{4-1}+(4-1)^{2}\\a_{4}=a_{3}+9\\a_{4}=14$

This is also true at the given value of 'n'.

Therefore, the recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

3 0

3 years ago

8.546 rounded to the nearest hundredth

Thepotemich [5.8K]

Answer:

8.55

Step-by-step explanation:

6 0

3 years ago