3 years ago

Can anyone help me!?!?!?!?! Here is my question:

1 answer:

8 0

The sine function has a minimum value of -1, so f(x) = 4sin( ) -1 will have a minimum value of -5.

g(x) obviously has a minimum value of -3.

h(x) has a squared term that cannot be negative, so its minimum value is +4.

f(x) has the smallest minimum value.

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which of the following gives an equation of a line that passes through the point (6 over 5, -19 over 5) and is parallel to the l

victus00 [196]

One equation for this would be

$y = \frac{41}{16} x-\frac{55}{8}$

We start by finding the slope between the two points:

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{-12-\frac{-19}{5}}{-2-\frac{6}{5}}
\\
\\=(-12+\frac{19}{5}) \div (-2-\frac{6}{5})
\\
\\=(\frac{-60}{5}+\frac{19}{5}) \div (\frac{-10}{5}-\frac{6}{5})
\\
\\=\frac{-41}{5} \div \frac{-16}{5}=\frac{-41}{5} \times \frac{-5}{16}=\frac{41}{16}$

A line parallel to this one will have the same slope. We will use point-slope form to write our equation:

$y-y_1=m(x-x_1)
\\
\\y-\frac{-19}{5}=\frac{41}{16}(x-\frac{6}{5})
\\
\\y+\frac{19}{5}=\frac{41}{16}x- \frac{41}{16} \times \frac{6}{5}
\\
\\y+\frac{19}{5}=\frac{41}{16}x-\frac{246}{80}
\\
\\y+\frac{304}{80}=\frac{41}{16}x-\frac{246}{80}
\\
\\y=\frac{41}{16}x-\frac{246}{80}-\frac{304}{80}
\\
\\y=\frac{41}{16}x-\frac{550}{80}
\\
\\y=\frac{41}{16}x-\frac{55}{8}$

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Distribute and evaluating <br> (X + 6) (x - 3)

sesenic [268]

Answer:

x^2+3x-18

Step-by-step explanation: hoped I helped

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David rented a truck for one day there was a base base fee of $19.99 and there was an additional charge of $.84 for each mile dr

MissTica

196 Miles

184.63-19.99=164.64

164.64/.84= 196

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Step-by-step explanation:

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