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VARVARA [1.3K]
3 years ago
5

Please help will give brainliest

Mathematics
1 answer:
vlada-n [284]3 years ago
7 0

Answer:

B

Step-by-step explanation:

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can someone please answer my recent question I need help I can't do it, call me stu.pid all you want cuz I am my du.mb brain can
Digiron [165]

Answer:

ok, I will help gladly

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
an angle measures 24° less than the measure if a supplementary angle . what is the measure of each angle​
vagabundo [1.1K]

Hey there!

If two angles are supplementary, that means that the measures of the two angles have a sum of 180.

If the two angles were of equal measure, they would both be 90 degrees.

The easiest way to get this would be to subtract 12 degrees from one 90 degree angle and add them to the other 90 degree angle so one angle has 24 more degrees then the other.

90 - 12 = 78

90 + 12 = 102

Let's check to make sure this works.

102 + 78 = 180 That checks out.

102 - 24 = 78 That also works.

So, the measures of the angles are 102 and 78.

Hope this helps!

4 0
3 years ago
I would like to know what this means exactly, feel free to answer it too
LiRa [457]

Answer:

A(-5,2)

Step-by-step explanation:

What they want from you is to basically just flip the graph 90 degrees

4 0
3 years ago
The junior varsity football team score 23 points in last Saturday's game they score the combination of seven point touchdowns in
frutty [35]

Answer:

  2 touchdowns, 3 field goals

Step-by-step explanation:

The number of touchdowns cannot be more than 3, so it is relatively easy to find the solution by trial and error.

  23 is not divisible by 3, so 0 touchdowns is not a solution

  23 -7 = 16 is not divisible by 3, so 1 touchdown is not a solution

  23 -14 = 9 is divisible by 3, so 2 touchdowns and 3 field goals is a solution

  21 -21 = 2 is not divisible by 3, so there is only one solution.

7 0
3 years ago
How do you find DE, Round to nearest 10th
Sergeu [11.5K]

Answer:  DE\approx6.0

Step-by-step explanation:

Observe in the figure given in the exercise that four right triangles are formed.

In this case you can use the following Trigonometric Identity to solve this exercise:

cos\alpha=\frac{adjacent}{hypotenuse}

From the figure you can identify that:

\alpha =53\°\\\\hypotenuse=10\\\\adjacent=BE=DE

Then, you can substitute values:

cos(53\°)=\frac{DE}{10}

The next step is to solve for DE in order to find its value. This is:

10*cos(53\°)=DE\\\\DE=6.01

Finally, rounding the result to the nearest tenth, you get that this is:

DE\approx6.0

7 0
3 years ago
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