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Cloud [144]
3 years ago
15

When a building casts a 20 meter shadow, a woman that is 1.8 meters tall casts a shadow that is 2.4 meters long. What is the dif

ference in the height of the building and it's shadow length? ​
Mathematics
1 answer:
LuckyWell [14K]3 years ago
3 0

Answer:

Difference = 5 meters

Step-by-step explanation:

Given that:

Length of shadow of building = 20 meter

Height of woman = 1.8 meters

Shadow length of woman = 2.4 meters

Height of building = x

Ratio of building's height to shadow = x : 20

Ratio of woman's height to shadow = 1.8 : 2.4

x : 20 :: 1.8 : 2.4

Product of mean = Product of extreme

20 * 1.8 = 2.4x

2.4x = 36

Dividing both sides by 2.4

\frac{2.4x}{2.4}=\frac{36}{2.4}\\x=15

Difference in height and shadow = 20 - 15 = 5 meters

Hence,

Difference = 5 meters

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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box with a square base and open top must have a volume of 4,000 cm3. Find the dimensions of the box (in cm) that minimize the am
Naya [18.7K]

Answer:

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Step-by-step explanation:

Since the box has a square base, let length = width = x. Also, let the height = y, therefore:

The volume of box = width * length * height

4000 = x * x * y

4000 = x²y

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The surface area (SA) = area of the base + sum of the area of each side

SA = x² + xy + xy + xy + xy

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substitute y = 4000/x²

SA = x² + 4x(4000/x²)

SA = x² + 16000/x

Taking the derivative:

SA' = 2x - 16000/x²

making SA' = 0:

0 = 2x - 16000/x²

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x³ = 8000

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Step-by-step explanation:

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