No he is wrong there will be 150000000 bacteria on it at 2 minutes
WORK:
2 min=120 sec
120 divided by 15=8
15 times 10 (7 times)
u get 150,000,000
1 5/8 = 13/8
(13/8)/14 = .116 or 13/112
.116 (26) = 3.016 or 169/56
Answer:
a) $520
b) $580
c) Interest amount is same each year
Step-by-step explanation:
Given - Georgie put $500 in her savings account, earning interest at a rate of 4% each year. She did not make any more deposits or withdrawals.
To find - a) How much money was in the account after one year?
b) How much money was in the account after 4 years?
c) Was the amount of money earned in interest the same or different each year?
Proof -
Here given that,
Principal amount = $500
rate of interest = 4% = 4/100 = 0.04
Now,
a)
Amount = P [ 1 + RT ]
= 500 [ 1 + 0.04(1)]
= 500 [ 1 + 0.04] = 520
⇒Amount = $520
b)
Amount = P [ 1 + RT ]
= 500 [ 1 + 0.04(4)]
= 500 [ 1 + 0.16] = 580
⇒Amount = $580
c)
In 2nd year,
Amount = P [ 1 + RT ]
= 500 [ 1 + 0.04(2)]
= 500 [ 1 + 0.08] = 540
⇒Amount = $540
Now,
Interest in 1st year = 520 - 500 = 20
Interest in 2nd year = 540 - 520 = 20
So,
The interest amount is same each year
Answer: $4,365.10
Step-by-step explanation:
Ok, we know that:
The account starts with $2350
There is a simple interest of 3.75% (or 0.035).
Then after one year, the amount in the account will increase by 3.75%, this means that the amount will be:
$2350 + 0.035*$2350 = (1.035)*$2350.
After another year, we have the same increase (but applied to the new amount in the account):
(1.035)*$2350 + 0.035*(1.035)*$2350. = (1.035)^2*$2350
And so on.
You already can see the pattern here, the amount of money in the saving account after N years will be:
M(N) = $2350*(1.035)^N.
Now we can answer:
what is the balance of the account if it earns a simple interest of 3.75% for 18 years?
Just replace N by 18 in that equation:
M(18) = $2350*(1.035)^18 = $4,365.10
Answer:
x=-20
Step-by-step explanation:
x+8−8=−12−8
x=−20
