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2 years ago

14

You go the grocery and purchase 13 boxes of chocolates. You also buy a game that costs $54.27. When you check out, the total cos

t is $98.34. How much does one box of chocolates cost?

1 answer:

Nikitich [7]2 years ago

6 0

98.34-54.27= 14.07

14.07÷13

Answer=3.39

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Ann started reading at 4:00 and finished at 4:20 p.M. Through what fraction of a circle did the minute hand turn?

nikitadnepr [17]

Answer:

1/3

Step-by-step explanation:

Turned 20 minutes, so the minute hand turned 20 times per hour

There are 60 minutes in 1 hour, so the minute hand turns 60 times per hour

Therefore, the fraction is 20/60, simplified to 1/3

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3 years ago

What is 16% of 90?<br> Please write how you did it

marin [14]

You first set up a proportion

16/100 = x/90

then cross multiply 16*90
and 100*x
1440 = 100x
divide each side by 100
1440/100 = 100x/100
100 cancels out on the right side
the answer is
14.4=x

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2 years ago

Read 2 more answers

Select all that apply.

astraxan [27]

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3 years ago

Read 2 more answers

Tracy works 20 hours a week at the bowling alley and makes $8.55 an hour. She gets a raise of $1.30 an hour. Approximately how m

NeTakaya

20 x 8.55= 171 that is what tracy was making per week.
8.55 + 1.30= 9.85 is her raise
20 x 9.85= 197 is how much she making with her new raise per week.
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8 0

2 years ago

valentinak56 [21]

Answer:

4

Step-by-step explanation:

This is an <em>infinite geometric series</em>. This has a sum of $\frac{a}{1-r}$

Where

a is the first term, and

r is the common ratio (one term divided by the previous term)

Let's figure out the first 2 terms by plugging in n = 1 first and then n = 2 for the series.

<u />

<u>First term:</u>

$3(\frac{1}{4})^{n-1}\\=3(\frac{1}{4})^{1-1}\\=3(\frac{1}{4})^0\\=3(1)\\=3$

<u>Second term:</u>

$3(\frac{1}{4})^{n-1}\\=3(\frac{1}{4})^{2-1}\\=3(\frac{1}{4})^1\\=3(\frac{1}{4})\\=\frac{3}{4}$

<em>Let's see the common ratio: $\frac{\frac{3}{4}}{3}\\=\frac{3}{4}*\frac{1}{3}\\=\frac{1}{4}$ </em>

<em />

<em>Thus we have a = 3 and r = 1/4</em><em>. Plugging into the formula of the infinite sum, we get:</em>

<em> $s=\frac{a}{1-4}=\frac{3}{1-\frac{1}{4}}=\frac{3}{\frac{3}{4}}=3*\frac{4}{3}=4$ </em>

<em />

<em>So, </em><em>the answer is 4</em>

4 0

2 years ago