Question

How do I find the inverse of this problem?

Answer 1

$\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the Inverse of real function.

Let's consider here, g(n) = y ,

so we get as,

$y = \sqrt[3]{ \frac{n - 1}{2} }$

no, cubing the power both side we get as,

=>

${y}^{3} = \frac{n - 1}{2}$

now,

$2 {y}^{3} = n - 1$

so finally, we get as,

=>

$n = 2 {y}^{3} + 1$

hence,here, n = inverse of the g(n) function.

so,

g^-1 (n) = 2y^3+1.