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Step2247 [10]
3 years ago
12

Yani buys 4 dozen flyers for $7.25. What is the cost for 12 dozen

Mathematics
1 answer:
zimovet [89]3 years ago
6 0
$21.75

4x3=12

7.25x3=$21.75
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Given the sample −4, −10, −16, 8, −12, add one more sample value that will make the mean equal to 3.
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Answer: The value to add to the set is 52

=======================================================

For a moment, ignore the extra value we'll add in later.

The given set of values add to -34.

Let x be the extra value we add in. It adds to the -34 to get -34+x, then we divide by 6 because the set {-4,-10,-16,8,-12,x} has 6 items.

So we get the mean (-34+x)/6

Set this equal to the mean we want (3) and solve for x

(-34+x)/6 = 3

-34+x = 6*3

-34+x = 18

x = 18+34

x = 52

The set {-4,-10,-16,8,-12,x} updates to {-4,-10,-16,8,-12,52} and this set has a mean of 3.

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which data set has a variation, or mean absolute deviation, similar to the data set given on the dot plot
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In the diagram, AITP - ANGO. Find the values of<br> x and y.<br><br> y =<br> X=
Zepler [3.9K]

Answer:

x = 25, y = 9

Step-by-step explanation:

Since the triangles are congruent then corresponding angles and sides are congruent, thus

∠ O = ∠ P , substitute values

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6y = 54 ( divide both sides by 6 )

y = 9

and

NG = IT , that is

x - 2y = 7 ( substitute y = 9 into the equation )

x - 2(9) = 7

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7 0
3 years ago
Complete the steps to solve the polynomial equation x3 – 21x = –20. According to the rational root theorem, which number is a po
jeka94

Answer:

Zeroes : 1, 4 and -5.

Potential roots: \pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20.

Step-by-step explanation:

The given equation is

x^3-21x=-20

It can be written as

x^3+0x^2-21x+20=0

Splitting the middle terms, we get

x^3-x^2+x^2-x-20x+20=0

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Therefore, the zeroes of the equation are 1, 4 and -5.

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Constant = 20

Factors of constant ±1, ±2, ±4, ±5, ±10, ±20.

Leading coefficient= 1

Factors of leading coefficient ±1.

Therefore, the potential root of the polynomial are \pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20.

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3 years ago
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