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3 years ago

Which number is irrational?

1 answer:

6 0

The answer would be: A) square root of 12

the square root of 12 is about 3.4641, irrational numbers most often have decimal points

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The Davidson family wants to expand its regular patio which currently measures 15 ft by 12 ft they want to expand the length and

Juli2301 [7.4K]

Answer:

L and W +5

Step-by-step explanation:

A1=15*12=180

A2=160+A1=340

340 factors

340,1,2,170,5,..., 20,17

20*17=340

|15-20|=5

|12-17|=5

add 5

4 0

3 years ago

What is the solution to the system of equations

Leni [432]

When system of equations solved graphically, the solutions are points of interceptions, So here, the solution is the point of interception (0,-5).

Answer (0,-5).

5 0

3 years ago

What is the greatest commen factor of 30 and 54

seropon [69]

54. 30
^ ^
27 2. 10 3
^ ^
9 3. 5 2
^
3 3
They only have 3 and two in common when you fully factor them. 3×2= 6
6 is the greatest common factor.

3 0

3 years ago

Read 2 more answers

Work out the value of 10 fourths

lora16 [44]

Answer:

10/4 equals 2 1/2 when simplified.

Step-by-step explanation:

10/4 = 2 2/4 or 2 1/2 when simplified.

This is because, 4 x 2 = 8, and 8 + 2 (or 1/2 of 4) = 10.

Hope this helps! :D

5 0

2 years ago

There are a total of 64 students in a drama club and a yearbook club. The drama club has 10 more students than the yearbook club

ivolga24 [154]

Answer:

The system of equations are $x+y=64$ and $x=y+10$

Step-by-step explanation:

Given : There are a total of 64 students in a drama club and a yearbook club. The drama club has 10 more students than the yearbook club.

To find : Write a system of linear equations that represents the situation.

Solution :

Let x represent the number of students in the drama club

and y represent the number of students in the yearbook club.

There are a total of 64 students in a drama club and a yearbook club.

i.e. $x+y=64$ ....(1)

The drama club has 10 more students than the yearbook club.

i.e. $x=y+10$ ....(2)

Substitute the value of (2) in (1),

$y+10+y=64$

$2y=54$

$y=\frac{54}{2}$

$y=27$

Substitute in (2),

$x=27+10$

$x=37$

Therefore, the system of equations are $x+y=64$ and $x=y+10$

8 0

3 years ago