Answer:
140
Step-by-step explanation:
When working HCF and LCM problems, I like to think in terms of this little diagram:
(a [ b ) c]
It shows me one of the numbers is ab, the other is bc, the HCF is b and the LCM is abc. "a" and "c" must be relatively prime for "b" to be the HCF.
__
Here, we're given ...
b = 20
ab = 320
abc = 2240
Then ...
c = abc/(ab) = 2240/320 = 7
x = bc = 20(7) . . . . . . equivalently, x = (abc·b)/(ab) = (2240·20)/320
x = 140
Answer:
f(-2) = 11
Step-by-step explanation:
Hello!
We can evaluate y by plugging in -2 for x in the equation.
<h3>Evaluate</h3>
- f(x) = 8|x| - 5
- f(-2) = 8|-2| - 5
- f(-2) = 8(2) - 5 Remember that absolute value turns the number positive
- f(-2) = 16 - 5
- f(-2) = 11
The evaluated value is 11.
Answer:
Multiply 1240 by 1.15 to get 1426 students enrolled this year.
:
X-4y=1
2x+y=11
ok so you have x-4y=1 and 2x+y=11
3x-3y=12 is your answer
2+12a. When adding, you're only collecting "like terms".