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luda_lava [24]
3 years ago
5

Which of the following shows the Addition Property of Equality?

Mathematics
1 answer:
zavuch27 [327]3 years ago
7 0

By definition we have to:

Addition Property of Equality is a property that allows you to add the same number to both sides of the equation. This number is added on both sides in order not to alter the equality.

Therefore, the following equation uses this property:

16x-2 + 2 = 18 + 2

We note that 2 is added to both sides of equality.

Rewriting we have:

16x = 20

Answer:

the following shows the Addition Property of Equality

B.) 16x-2 + 2 = 18 + 2

16x = 20

You might be interested in
HCF(320, x) = 20, LCM(320, x) = 2240, then x =
HACTEHA [7]

Answer:

  140

Step-by-step explanation:

When working HCF and LCM problems, I like to think in terms of this little diagram:

  (a [ b ) c]

It shows me one of the numbers is ab, the other is bc, the HCF is b and the LCM is abc. "a" and "c" must be relatively prime for "b" to be the HCF.

__

Here, we're given ...

  b = 20

  ab = 320

  abc = 2240

Then ...

  c = abc/(ab) = 2240/320 = 7

  x = bc = 20(7) . . . . . . equivalently, x = (abc·b)/(ab) = (2240·20)/320

  x = 140

6 0
3 years ago
F(x) = 8|x| - 5<br> f(-2) =
Anastaziya [24]

Answer:

f(-2) = 11

Step-by-step explanation:

Hello!

We can evaluate y by plugging in -2 for x in the equation.

<h3>Evaluate</h3>
  • f(x) = 8|x| - 5
  • f(-2) = 8|-2| - 5
  • f(-2) = 8(2) - 5         Remember that absolute value turns the number positive
  • f(-2) = 16 - 5
  • f(-2) = 11

The evaluated value is 11.

6 0
1 year ago
The enrollment at a community college this year is 115% of last year’s enrollment. If there were 1,240 students enrolled at the
wlad13 [49]

Answer:

Multiply 1240 by 1.15 to get 1426 students enrolled this year.

:

5 0
2 years ago
Can someone help me on this one Please
Mumz [18]
X-4y=1
2x+y=11
ok so you have x-4y=1 and 2x+y=11
3x-3y=12 is your answer
6 0
3 years ago
Help what's the answer to 2 + 3a + 9a? 2+2a? Or 14a?
bulgar [2K]
2+12a. When adding, you're only collecting "like terms".
3 0
3 years ago
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