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LUCKY_DIMON [66]
3 years ago
15

PLEASEE I NEEEEDD HEELLLPP

Mathematics
1 answer:
KonstantinChe [14]3 years ago
3 0

Answer:

A. please give brainliest I need it.

Step-by-step explanation:

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How much longer is 108 inches from 98 inches
WARRIOR [948]

Answer:

b.10 inches

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
In care cadrane se afla graficul functiei ; f:(x)=121x
iragen [17]
<span>Solución X = {0, 121}
</span><span>espero que esto ayude</span>
8 0
3 years ago
The mean temperature for the first 7 days in January was 3 °C.
g100num [7]

Answer:

<u><em>3.5 °C</em></u>

Step-by-step explanation:

  • To find the answer multiply 3 and 7 to get the sum of the temperatures in the first seven days.

        3 x 7 = 21

  • Add 21 and 8 together to get the sum of the temperatures in the first 8 days.

        21 + 8 =29

  • Divide 29 by 8 to get the mean temperature for the first eight days.

       29 ÷ 8 = 3.5

       3.5 °C

8 0
3 years ago
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A test consists of 10 true/false questions. To pass the test a student must answer at least 88 questions correctly. If a student
Zanzabum

Answer:

The probability that the student is going to pass the test is 0.0545

Step-by-step explanation:

The variable that says the number of correct questions follows a Binomial distribution, because there are n identical and independent events with a probability p of success and a probability 1-p of fail. So, the probability of get x questions correct is:

P(x)=\frac{n!}{x!(n-x)!} *p^{x} *(1-p)^{n-x}

Where n is equal to 10 questions and p is the probability of get a correct answers, so p is equal to 1/2

Then, if the student pass the test with at least 8 questions correct, the probability P of that is:

P = P(8) + P(9) + P(10)

P=(\frac{10!}{8!(10-8)!}*0.5^{8}*(0.5)^{10-8})+(\frac{10!}{9!(10-9)!} *0.5^{9} *(0.5)^{10-9})+(\frac{10!}{10!(10-10)!} *0.5^{10} *(0.5)^{10-10})

P = 0.0439 + 0.0097 + 0.0009

P = 0.0545

8 0
3 years ago
X-intercepts y = (3x+8) (5x-3) (x+1)
Anna [14]
(-8/3,0) ; (3/5,0) ; (-1,0)
6 0
3 years ago
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