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aksik [14]
3 years ago
5

HELP ANYONE PLEASEEEEE !!!

Mathematics
2 answers:
UkoKoshka [18]3 years ago
4 0

Answer:

its the second one down

Step-by-step explanation:

Monica [59]3 years ago
3 0

Answer: B

Step-by-step explanation: the y-intercept is -3 and the slope is 1/2 you do rise over run so is -2-(-3)/2-0 to get 1/2

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The ratio of the number of peas Julia had to the number of peas Vlada had was 3:2. After Julia gave Vlada 15 peas, she still had
inn [45]
J:V = 3:2

3:2 x 40 = 120:80

J: 120-15 = 105
V:  80+15 = 95

J:V is now 105:95

The original amount of peas that Julia had at first was 120.
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3 years ago
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What is the midpoint of the line segment wit endpoints (5,6) and (-2,-6)?
Nadya [2.5K]

Answer: 4,5 i think..

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What is the equation of circle C???
BigorU [14]

Answer:

(x-5)²+(y-7)²=80

Step-by-step explanation:

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In the diagram below, assume that all points are given in rectangular coordinates. Determine the polar coordinates for each poin
Korolek [52]

Step-by-step explanation:

We have cartisean points. We are trying to find polar points.

We can find r by applying the pythagorean theorem to the x value and y values.

r  {}^{2} =  {x}^{2}  +  {y}^{2}

And to find theta, notice how a right triangle is created if we draw the base(the x value) and the height(y value). We also just found our r( hypotenuse) so ignore that. We know the opposite side and the adjacent side originally. so we can use the tangent function.

\tan(x)  =  \frac{y}{x}

Remeber since we are trying to find the angle measure, use inverse tan function

\tan {}^{ - 1} ( \frac{y}{x} )  =

Answers For 2,5

{2}^{2}  +  {5}^{2}  =  \sqrt{29}  = 5.4

So r=sqr root of 29

\tan {}^{ - 1} ( \frac{5}{2} )  = 68

So the answer is (sqr root of 29,68).

For -3,3

{ -3 }^{2}  +  {3}^{2}  =  \sqrt{18}  = 3 \sqrt{2}

\tan {}^{ - 1} ( \frac{3}{ - 3} )  =  - 45

Use the identity

\tan(x)  =  \tan(x + \pi)

So that means

\tan(x)  = 135

So our points are

(3 times sqr root of 2, 135)

For 5,-3.5

{5}^{2}  +  {3.5}^{2}  =  \sqrt{37.25}

\tan {}^{ - 1} ( \frac{ - 3.5}{ - 5} )  = 35

So our points are (sqr root of 37.25, 35)

For (0,-5.4)

{0}^{2}  +  { - 5.4}^{2}  = \sqrt{}  29.16 = 5.4

So r=5.4

\tan {}^{ - 1}  (0)  = undefined

So our points are (5.4, undefined)

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3 years ago
Which complex number lies below the real axis and to the right of the imaginary axis:
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3-i.........................................
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