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3 years ago

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Mathematics

2 answers:

Ivenika [448]3 years ago

8 0

Answer:

Step-by-step explanation:

180÷3=60

x=60

............

Radda [10]3 years ago

8 0

Answer:

x+x+x=180°

3x=180°

x=60°

Step-by-step explanation:

The sum of three angles of triangle is 180°

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The triangle on the right is a scaled copy of the triangle on the left. Identify the scale

Sveta_85 [38]

Answer:

the scale factor is 4 to 1, or just 4.

Step-by-step explanation:

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3 years ago

What is the remainder of 10^2017 divided by 1001?

pashok25 [27]

Note: When I use the double equal sign, I mean the triple bar used with modular arithmetic

10^3 = 1000 == -1 (mod 1001)
10^3 == -1 (mod 1001)
(10^3)^672 == (-1)^672 (mod 1001)
(10^(3*672) == 1 (mod 1001)
10^2016 == 1 (mod 1001)
10*10^2016 == 10*1 (mod 1001)
10^2017 == 10 (mod 1001)

Final Answer: 10

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3 years ago

Multiply 3(2x - 1)(x + 2)

Andrei [34K]

(6x-3)(3x+6)

Explanation:

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3 years ago

Translate this phrase into an algebraic expression.

Andreas93 [3]

Answer:

4m-8

Step-by-step explanation:

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3 years ago

Jack works as a waiter and is keeping track of the tips he earns daily. about how much does jack have to earn in tips on sunday

OLga [1]

A mean is an arithmetic average of a set of observations. The amount that Jack has to earn in tips on Sunday if he wants to average $19 a day is $25.

A mean is an arithmetic average of a set of observations. it is given by the formula,

$\rm Mean=\dfrac{\text{Sum of all obervation}}{\text{Number of observation}}$

As it is given that Jack makes $12 on Monday, $14 on Tuesday, $18 on Wednesday, $16 on Thursday, $26 on Friday and $22 on Saturday. And we need to know how much he should earn on Sunday, so the average is $19. Therefore, we can write,

$\rm Mean=\dfrac{\text{Sum of all obervation}}{\text{Number of observation}}$

$19 = \dfrac{12+14+18+16+26+22+x}{7}\\\\133 = 108 + x\\\\133-108=x\\\\x = 25$

Hence, the amount that Jack has to earn in tips on Sunday if he wants to average $19 a day is $25.

Learn more about Mean:

brainly.com/question/16967035

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2 years ago

HELPPPPPP PLEASEEEEEEEE IM BEGGGINGGGG SOMEONE I REALLY NEED HELPPPPP PLEASEEEEEEEEEEEE PLEASEEEEE​

HELPPPPPP PLEASEEEEEEEE IM BEGGGINGGGG SOMEONE I REALLY NEED HELPPPPP PLEASEEEEEEEEEEEE PLEASEEEEE