A user must seek support when troubleshooting a computer problem is beyond his or her technical knowledge because: <em>When the user seeks support, the computer problem is solved accordingly and further complications are avoided.</em>
Discussion:
Further computer problems may arise from a computer problem. As such, when a user finds it difficult to troubleshoot a computer problem, the user should seek support since the computer problem is beyond his or her technical knowledge
Read more on troubleshooting:
brainly.com/question/18315517
Answer: There are four types of operators in QBASIC. They are Arithmetic Operators, Relational Operators, Logical Operators and Sting Operator. a. Arithmetic Operators. Arithmetic Operators are used to perform mathematical calculations like addition, subtraction, division, multiplication and exponential. :)
Answer:
Internet data transfer.
Explanation:
Optical fibre can be used to move information from one place to another. It is used in internet communications, cable television broadcasting, and telephone communication. One common application is for the transfer of data over the internet. Chances are your browser was able to download this web page by receiving data that came from Brainly's servers, and from my computer, through a fibre optic cable.
Answer:
1) Right-click the slide, select Layout, and select Two Content
2) <em>*While on the same slide* </em>-go to the Ribbon, select Layout and select Two Content.
Explanation:
Either of these options will change the layout of the slide. After this is done, select 8-14 and cut and paste them in the second text box. Then format them to look aesthetically pleasing.
Answer:
2.342m
Explanation:
Given
Time = 0.5 s
Height of Window = 2m
Because the pot was in view for a total of 0.5 seconds, we can assume that it took the cat 0.25 seconds to go from the bottom of the window to the top
Using this equation of motion
S = ut - ½gt²
Where s = 2
u = initial velocity = ?
t = 0.25
g = 9.8
So, we have.
2 = u * 0.25 - ½ * 9.8 * 0.25²
2 = 0.25u - 0.30625
2 + 0.30625 = 0.25u
2.30625 = 0.25u
u = 2.30625/0.25
u = 9.225 m/s ------------ the speed at the bottom of the pot
Using
v² = u² + 2gs to calculate the height above the window
Where v = final velocity = 0
u = 9.225
g = 9.8
S = height above the window
So, we have
0² = 9.225² - 2 * 9.8 * s
0 = 85.100625 - 19.6s
-85.100625 = -19.6s
S = -85.100625/19.6
S = 4.342
If 4.342m is the height above the window and the window is 2m high
Then 4.342 - 2 is the distance above the window
4.342 - 2 = 2.342m
