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Leona [35]
3 years ago
10

Help please! write in terms of i​

Mathematics
2 answers:
Andrew [12]3 years ago
5 0

Answer:

2√10i

Step-by-step explanation:

√-40 = √40 × √-1

= √(4 × 10) × √-1

= √4 × √10 ×√-1

<em>√-1 = i</em>

√40 = 2√10i

Varvara68 [4.7K]3 years ago
4 0
Hope this helps (2i square root of 10)

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ivann1987 [24]

For the top angles you would solve them by setting them equal to each other, so you would do 3x+5=17x-70. You can then add 70 to both sides, getting 3x+75=17x. You can then subtract 3x from both sides, getting 75=14x. You then divide both sides, getting 5 5/14 or around 5.36 as x. You can then add plug that into 3x+5, getting around 21.07. You can then make the equation R=180-21.07. You'd get 158.93.

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3 years ago
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valkas [14]
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Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

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ddd [48]

Answer:

12 x 12 = 144

Step-by-step explanation:

12 times by 12 is 144

8 0
2 years ago
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Bumek [7]

972 / 3 = $324

Which means that each person will pay $324

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3 years ago
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