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OverLord2011 [107]
3 years ago
5

25 ate only breakfast, 15 ate only lunch, 50 ate only dinner, 60 ate only lunch and breakfast, 225 ate only lunch and dinner, 50

0 ate only dinner and breakfast, 240 ate all three meals in the cafeteria.
. P(did not eat in the cafeteria) what is the possibility
Mathematics
1 answer:
andrew11 [14]3 years ago
6 0

Answer:so u asking how much was ate total?

Step-by-step explanation:

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Hi I’m doing IXL and I’m having trouble with this one
maria [59]

Answer:

They are not equivalent.

Step-by-step explanation:

5:2 = 2,5

8:3 = 2,66...

8 0
3 years ago
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Rewrite the set M by listing its elements. Make sure to use the appropriate set notation
Anika [276]
We are given the rule for the set,
M= {x | x is an integer and -2 < x < 1}In words, this set translates to numbers that are integers and greater than -2 but less than 1.
The actual elements of the set are
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There are only two elements.
8 0
3 years ago
NEED HELP IN MATH .THANKS
stira [4]
It's simple. as long as it's a 10 you just put in however many 0 it has as the root to a 1. or just multiply it however many times.
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6 0
3 years ago
Given a group of 8 women and 11 men, how many different ways are there of choosing one man and one woman for a committee?
Mashutka [201]
Any of the 11 man can be chosen, and combined with any of the 8 women.

Assume we select man1. The selected committee can be:

(m1,w1), (m1,w2), (m1,w3), (m1,w4), (m1,w5), (m1,w6), (m1,w7), (m1,w8), 

so there are 8 committees selections with man1 in them.

we could repeat the same procedure for the remaining 10 men, and get 8 committees where each of them is a member.

so there are 11*8=88 ways of choosing 1 man and 1 woman.


Answer: 88
8 0
4 years ago
6,132 ÷ 203= Divide. Enter a solution as a mixed number
Marat540 [252]

Answer:

30.2

Step-by-step explanation:

7 0
3 years ago
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