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Basile [38]
3 years ago
11

There are 3 times more kittens than puppies in a box. Together there are 24 animals. How many kittens are there?

Mathematics
1 answer:
Paha777 [63]3 years ago
6 0

kitten : puppies

3:1

<em>Total</em><em> </em><em>no</em><em>.</em><em> </em>

3+1 = 4

<em>Ther</em><em>efore</em>

24÷4 = 6

(each of ratio represent 6 animals)

<em>So</em><em>,</em>

3×6

= 18

Answers

18 kitten

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beks73 [17]
2.25 ounces...18/8=2.25

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3 years ago
Harper deposited $110 into a savings account that earns 3.5% interest a year. The function (R)t models the amount of money Raymo
schepotkina [342]

Answer:

  A.  $2.26

Step-by-step explanation:

An equation for Harper's balance can be written similar to the one written for Raymond's balance. It will be ...

  H(t) = 110(1.035)^t

For t = 2, the two balances will be ...

  H(2) = 110(1.035^2) = 117.83

  R(2) = 110(1.025^2) = 115.57

The difference is ...

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Harper's account will have $2.26 more.

_____

As a quick estimate or sanity check, you can see that Harper's interest rate is 1% more than Raymond's. So, in 2 years, he will earn a little more than 2% more on his investment than Raymond earns. 2% of $110 is $2.20, so the difference can be expected to be slightly more than this.

7 0
3 years ago
Try it
Valentin [98]

Answer:

(x,y) + (x-4, y)

Step-by-step explanation:

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4 0
3 years ago
A town has a population of 32,000 in the year 2002; 38,400 in the year 2003; 46,080 in the year 2004; and 55,296 in the year 200
NeTakaya
The point is to find the growth rate. The compound formula is:

P=A(1+ growth rate)ⁿ, where A is the initial Value & P the new value after n years:
P₂₀₀₃ =P₂₀₀₂ (1+ growth rate)¹ (the period "n" from 2002 to 2003 being 1 year)

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You will balso find the same growth rate for:
P₂₀₀₄ = P₂₀₀₃(1+ growth rate)¹
P₂₀₀₅ = P₂₀₀₄((1+ growth rate)¹
between 2015 & 2002 THERE ARE 14 YEARS:

P₂₀₁₅ = P₂₀₀₂(1+0.2)¹⁴ & P₂₀₁₅ = 32000(1+02)¹⁴ = 410,854
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4 years ago
Please help!<br><br> The image is below.
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Answer:

A. False

B.False

C.True

D.True

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