Answer:
4.05% probability that a randomly selected adult has an IQ greater than 123.4.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
Probability that a randomly selected adult has an IQ greater than 123.4.
This is 1 subtracted by the pvalue of Z when X = 123.4. So
has a pvalue of 0.9595
1 - 0.9595 = 0.0405
4.05% probability that a randomly selected adult has an IQ greater than 123.4.
Answer:
(-4,9)
Step-by-step explanation:
substitute the given value for y into the first equation
x-5(-2x+1)=-49
distribute
x+10x-5=-49
add like terms
11x-5=-49
add 5 to both sides
11x=-44
divide both sides by 11
x=-4
now plug x into into the second equation
y=-2(-4)+1
y=8+1
add like terms
y=9
Is it asking you to tell them what the numbers that the letters substitute are??
If so o might be able to help with that
Answer: value of c = 5
Step-by-step explanation:
Part A Simplify:
Answer is - 12b + 6c + 18
Part B
Answer is (D)
Factor/simplify
- 12b + 6c + 18
6(- 2b + c + 3)
= (6)(- 2b + c + 3)
= (6)(- 2b ) + (6)(c) + (6)(3)
= - 12b + 6c + 18
therefore,- 12b + 6c + 18; Factored in GCF is 6(-2b + c + 3)
- 12b + 6c + 18
reorder the terms
18 + 12b + 6c
Factor out the GCF " 6"
6(3 + 2b + c)
Final Result:
6(3 + 2b + c)
Hope this helps
