Ask question

Ask question

All categories

3 years ago

14

Plz help I need answers as fast as possible

1 answer:

erastova [34]3 years ago

6 0

Answer:

Step-by-step explanation:

a). Set of vowels in English alphabets:

{a, e, i, o, u}

b). S = {x: x is a positive odd number less than 10}

S = {1, 3, 5, 7, 9}

c). T = {letters in the word "WOOD"}

T = {W, O, O, D}

You might be interested in

Gavin ran 5 3/4 miles yesterday. He ran 4 1/6 miles today. How many more miles did gavin run yesterday?

exis [7]

Answer:

1 and 7/12 or 1.583

Step-by-step explanation:

5 0

3 years ago

Find the lowest common multiple (LCM) of 28 and 35.

Ahat [919]

Step-by-step explanation: I would first create a factor tree for these numbers and break them down into their prime factorization.

First, 28 is 7 x 4 and 4 is 2 x 2

Next, 35 is 7 x 5

In our factors tree, a 7 is a factor that is shared so we pull out a 7.

Now, we multiply all of our factors that don't pair up

and in this case, that's a 2, another 2, and a 5.

So our LCM is 7 x 2 x 2 x 5 or 140.

4 0

3 years ago

Read 2 more answers

A wagon is on sale for 20% off. The sale price of the wagon is $114. What was the original price of the wagon assuming no sales

ivann1987 [24]

Answer:

$136.8

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Consider the circle of radius 5 centered at (0, 0). Find an equation of the line tangent to the circle at the point (3, 4) in sl

Wittaler [7]

Answer:

$\displaystyle y= -\frac{3}{4} x + \frac{25}{4}$ .

Step-by-step explanation:

The equation of a circle of radius $5$ centered at $(0,0)$ is:

$x^{2} + y^{2} = 5^{2}$ .

$x^{2} + y^{2} = 25$ .

Differentiate implicitly with respect to $x$ to find the slope of tangents to this circle.

$\displaystyle \frac{d}{dx}[x^{2} + y^{2}] = \frac{d}{dx}[25]$

$\displaystyle \frac{d}{dx}(x^{2}) + \frac{d}{dx}(y^{2}) = 0$ .

Apply the power rule and the chain rule. Treat $y$ as a function of $x$ , $f(x)$ .

$\displaystyle \frac{d}{dx}(x^{2}) + \frac{d}{dx}(f(x))^{2} = 0$ .

$\displaystyle \frac{d}{dx}(2x) + \frac{d}{dx}(2f(x)\cdot f^{\prime}(x)) = 0$ .

That is:

$\displaystyle \frac{d}{dx}(2x) + \frac{d}{dx}\left(2y \cdot \frac{dy}{dx}\right) = 0$ .

Solve this equation for $\displaystyle \frac{dy}{dx}$ :

$\displaystyle \frac{dy}{dx} = -\frac{x}{y}$ .

The slope of the tangent to this circle at point $(3, 4)$ will thus equal

$\displaystyle \frac{dy}{dx} = -\frac{3}{4}$ .

Apply the slope-point of a line in a cartesian plane:

$y - y_0 = m(x - x_0)$ , where

$m$ is the gradient of this line, and
$(x_0, y_0)$ are the coordinates of a point on that line.

For the tangent line in this question:

$\displaystyle m = -\frac{3}{4}$ ,
$(x_0, y_0) = (3, 4)$ .

The equation of this tangent line will thus be:

$\displaystyle y - 4 = -\frac{3}{4} (x - 3)$ .

That simplifies to

$\displaystyle y= -\frac{3}{4} x + \frac{25}{4}$ .

3 0

3 years ago

Could you please show the work for both of them?

lesantik [10]

7. y=-3/2x+8 (3rd answer choice)

substitute
-4=-3/2(8)+b
-4=-24/2 +b
-4=-12+b
+12 both sides
8=b

so equation would be...

y=-3/2x+8 (3rd answer choice)

8. y=-5x-17 (2nd answer choice)

substitute
-2=-5(-3)+b
-2=15+b
-15 both sides
-17=b

so the equation would be...

y=-5x-17 (2nd answer choice)

check your work by substituting each (x,y) value into the final equations if you want. hope this helps :))

3 0

3 years ago