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3 years ago

Assume the following information from a schedule of cost of goods manufactured:

Business

1 answer:

Evgesh-ka [11]3 years ago

3 0

Answer:

The manufacturing overhead applied to work in process is:

D. $79,000

Explanation:

a) Data and Calculations:

Beginning work in process inventory 30,000

Direct materials used in production 50,000

Direct labor 60,000

Total manufacturing costs to account for 219,000

Manufacturing overhead applied to WIP 79,000 (219,000 - 140,000)

Ending work in process inventory 72,000

b) The manufacturing overhead applied to Work in Process is the difference between the total manufacturing costs to account for and the costs of beginning work in process, direct materials, and direct labor for the period. When the ending work in process is deducted from the total manufacturing costs, the resulting figure represents the cost of goods transferred to finished goods inventory.

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Swifty Corporation reported net sales of $690000, $730000, and $828000 in the years 2016, 2017, and 2018, respectively. If 2016

Flura [38]

Answer:

120%

Explanation:

Given net sales;

Year 1996 = $690000

Year 1997 = $730000

Year 1998 = $828000

With 1996 as the base year, it means the percentage of any year can be computed by dividing the net sales for that year with the net sales for 1996 and expressing the results as a percentage.

1998 sales as a percentage of the base represents

= $828000/$690000

= 1.2

Expressed as a percentage, this is 120%.

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3 years ago

The price of gold is currently $1,200 per ounce. The forward price for delivery in one year is $1,400. An arbitrageur can borrow

max2010maxim [7]

Answer:

I Dont know

Explanation:

sorrrrrrry I will try next time

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2 years ago

Each machine must be run by one of 19 cross-trained workers who are each available 35 hours per week. The plant has 10 type 1 ma

Mrac [35]

Answer:

The Linear programming model is given as below

Profit Function: $P=90X+120Y+150Z$

Constraints:

$2X+2Y+Z\leq 400$

$3X+4Y+6Z\leq 240$

$4X+6Y+5Z\leq 320$

$\dfrac{2X+2Y+Z}{40}\leq 10$

$\dfrac{3X+4Y+6Z}{40}\leq 6$

$\dfrac{4X+6Y+5Z}{40}\leq 8$

$\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19$

Explanation:

As the question is not complete, the complete question is found online and is attached herewith.

Let the number of product 1 to be produced is X, that of product 2 is Y and product 3 is Z

so the maximizing function is the profit function which is given as

$P=90X+120Y+150Z$

Now as the number of hours in a week are 40 and there are a total of 10 type 1 machines so the total number of machine 1 hours are 40*10=400 hours

As from the given table product 1 uses 2 machine hours of machine 1, product 2 uses 2 machine hours of machine 1 and product 3 uses 1 hour of machine 1 so

$2X+2Y+Z\leq 400$

Now as the number of hours in a week are 40 and there are a total of 6 type 2 machines so the total number of machine 2 hours are 40*6=240 hours

As from the given table product 1 uses 3 machine hours of machine 2, product 2 uses 4 machine hours of machine 2 and product 3 uses 6 hour of machine 2 so

$3X+4Y+6Z\leq 240$

Now as the number of hours in a week are 40 and there are a total of 8 type 3 machines so the total number of machine 3 hours are 40*8=320 hours

As from the given table product 1 uses 4 machine hours of machine 3, product 2 uses 6 machine hours of machine 3 and product 3 uses 5 hour of machine 3 so

$4X+6Y+5Z\leq 320$

Now as the machine 1 is used as 2X+2Y+Z in a week and the week is of 40 hours so the number of machines to be used are given as

$\dfrac{2X+2Y+Z}{40}\leq 10$

Now as the machine 2 is used as 3X+4Y+6Z in a week and the week is of 40 hours so the number of machines to be used are given as

$\dfrac{3X+4Y+6Z}{40}\leq 6$

Now as the machine 3 is used as 4X+6Y+5Z in a week and the week is of 40 hours so the number of machines to be used are given as

$\dfrac{4X+6Y+5Z}{40}\leq 8$

Now the workers are available for 35 hours so the worker available at the machine 1 is given as

$\dfrac{2X+2Y+Z}{35}$

That of machine 2 is given as

$\dfrac{3X+4Y+6Z}{35}$

That of machine 3 is given as

$\dfrac{4X+6Y+5Z}{35}$

As the total number of workers is 19 so the constraint is given as

$\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19$

So the Linear programming model is given as below

Profit Function: $P=90X+120Y+150Z$

Constraints:

$2X+2Y+Z\leq 400$

$3X+4Y+6Z\leq 240$

$4X+6Y+5Z\leq 320$

$\dfrac{2X+2Y+Z}{40}\leq 10$

$\dfrac{3X+4Y+6Z}{40}\leq 6$

$\dfrac{4X+6Y+5Z}{40}\leq 8$

$\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19$

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3 years ago

What influence tactic depends on the strength of the friendship and between the influencers and the target?

Nutka1998 [239]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
I think the answer should be "Personal appeals". It is a<span>n influence tactic in which the requestor asks for something based on personal friendship or loyalty</span>

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3 years ago

Match each hypothetical country’s aging structure to its most likely economic situation.

worty [1.4K]

It should be noted that the aging structure data is important as it allows the rate of growth to be associated with the population in a country.

Your information is incomplete. Therefore, an overview of the topic will be given. There are typically three age structures which are:

The children who are under 15 years old.
The working-age who are between 15 - 64 years.
The elderly ones who are 65 years and older.

It should be noted that an aging population lower the labor-force participation and slows down economic development in the country.

Learn more about aging population on:

brainly.com/question/14540910

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3 years ago