All categories

2 years ago

If HF=4x+9, EF = 5x+3 , and EF is perpendicular to HF, solve for x.

Mathematics

1 answer:

Leno4ka [110]2 years ago

3 0

Answer:

x = 6

Step-by-step explanation:

HF = 4x + 9

EF = 5x + 3

Since FG is perpendicular to EH, ∆EFG and ∆HFG are congruent to each other.

Thus:

HF = EF

4x + 9 = 5x + 3 (substitution)

Collect like terms

4x - 5x = -9 + 3

-x = -6

Divide both sides by -1

x = 6

You might be interested in

Thank you. please answer asap!

PSYCHO15rus [73]

Answer:

96 i think

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Help me on 7 And 8 ASAP

Semmy [17]

Answer:7.)A

8.)C

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

7/3x+1/3x=1+5/3x plz help

liubo4ka [24]

(Multiply all by 3 )
7x+x=3+5x
8x=3+5x
3x=3
x=1

7 0

2 years ago

The length of a rectangle envelope is 2 1/2 times its width. A plastic band surrounds the front and back of the envelope to secu

Andreas93 [3]

Answer:

Length of the envelope = 14

Width of the envelope = 5.6

Step-by-step explanation:

Let the width of the rectangle be x

Then the length of the rectangle will be $2\frac{1}{2} \times x$

Also the length of the plastic band to cover the front and back of the envolpe = $39\frac{3}{8}$

To cover one side th band required is

=> $\frac{39\frac{3}{8}}{2}$

=> $\frac{\frac{315}{8}}{2}$

=> ${\frac{315}{16}$

=>39.4

We know that the perimeter of the rectangle is

=> 2( L + B) = ${\frac{39.4}{2}$

=> 2( $2\frac{1}{2} \times x + x$ ) = 19.7

=> 2( $\frac{7}{2}x) = 19.7$

=> $3.5x = 19.7$

=> $x = \frac{19.7}{3.5}$

=> $x = 5.6$

Now length of the envelope =

=> $2\frac{1}{2} \times x$

=> $2.5 \times 5.6$

=> 14

5 0

2 years ago

I need to know then measurement of c

sergey [27]

C is 666666688888 from my lookings. Jk

8 0

2 years ago

Read 2 more answers