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valkas [14]
3 years ago
12

HELP HELP HELP I will give all my points

Mathematics
1 answer:
olganol [36]3 years ago
6 0

Answer:

1/4 of a foot.

Step-by-step explanation:

This can't be a square because all sides of a square are equal. This is a rectangle.

Length = area / width.

= (8/12) / (8/3)         (because 2 2/3 = 8/3)

= 1/4 feet.

This is really the width as by definition length is greater than width.

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PLEASE HELP!!!! <br> Solve the system of equation. Write the solution as a coordinate point.
Dovator [93]

We can just substitute y = 4x+1 in the second equation.

6x-2(4x+1)=-3\\6x-8x-2=-3\\6x-8x-2+3=0\\-2x+1=0\\-2x=-1\\x=\frac{1}{2}

We know the value of x, substitute x in any equations to get the y-value.

4x+1=y\\4(\frac{1}{2})+1=y\\2+1=y\\3=y

The value of y is 3 and the value of x is 0.5 aka 1/2

Since you want the solution as a point then It's below here.

5 0
3 years ago
The mean of the weights of a group of 100 men and women
Arte-miy333 [17]

Answer:

Step-by-step explanation:

160lb.

The mean of the weights of a group of 100 men and women is 160lb. If the number of men in the group is 60 and the mean weight of the men is 180lb, what is the mean weight of the women? For a set of data, the lower quartile is 19, the median is 31, and the upper quartile is 48.

7 0
2 years ago
How to remember length times weigth
RoseWind [281]
I think you mean length times width, which is more simply written as lw.
6 0
3 years ago
The exchange rate is £1 =$1.54 how many $ would I get for £200
Andreyy89
Let's see, if 1 pound = $1.54, let's times 1.54 by 200, the answer is $308, hope this helps
3 0
3 years ago
Water is flowing into a large spherical tank at a constant rate. Let V (t) be the volume of water in the tank at time t, and h(t
aleksley [76]

Answer:

See solutions for detail.

Step-by-step explanation:

a.  \frac{dV}{dt} is the instantaneous rate of change of volume given with respect to time, t.

The volume's rate of change is written as a function of time.

-\frac{dh}{dt} is the rate of change in the height of water in the tank with respect to time, t.

b.  \frac{dV}{dt}- is the only constant. Water flows into the constant at a constant rate, say 6cm^3 per minute.

c. \frac{dV}{dt} is positive. Volume water in the take  is increasing from time to time.

-The volume at time t=1 is greater than the volume at t=0, hence, it's a positive rate of change.

d. \frac{dh}{dt} is a positive rate. The initial height of water in the tank is zero.

-The final height at time t is 0.25h. The height is increasing with time.

Hence, it is positive.

8 0
4 years ago
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