Kailynn has been on a roll, and solving 5 math problems every 2.5 minutes. At this rae, how many problem will she solve in 30 mi
1 answer:
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<u>Answer:</u>
Price of the adult's ticket = $13
Price of a child's ticket = $ 10
<u>Step-by-step explanation:</u>
Given:
Cost of train fares for Three adults and four children = $79
Cost of train fares Two adults and three children = $ 56
To Find:
Price of the adult's ticket and the price of a child's ticket =?
Solution:
Let the cost of one adult's ticket be x and
Let the cost of one child's ticket be y
Then
Three adults and four children must pay $ 79 be
3x + 4y = 79-----------------------------------------------(1)
Two adults and three children must pay $56
2x + 3y = 56----------------------------------------------(2)
multiply eq(1) by 2, we get
6x + 8y = 158----------------------(3)
multiply eq(2) by 3, we get
6x + 9y = 168----------------------(4)
Subracting (3) from (4)
6x + 9y = 168
6x + 8y = 158
(-) (-) (-)
------------------------------
0x + y = 10
------------------------------
y=10
Now substitute the value of y in eq (1) to get the value of x
3x + 4(10)= 79
3x + 40 = 79
3x = 79 - 40
3x = 39
x =
x= 13
Try this option:
note, that distance between the parallel sides is shown via formula of area.
If it is possible, check the arithmetic.
note, that distance between the parallel sides is shown via formula of area.
If it is possible, check the arithmetic.