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3 years ago

Y = 2x - 4x +3 Algebraically determine whether the function is even, odd or neither

Mathematics

1 answer:

Margarita [4]3 years ago

3 0

Answer:

i dont know srry

Step-by-step explanation:

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What is y=2(x+1)^2 in standard form

Setler79 [48]

Y=4x+4
I think this is it u just have to simplify to get it to y=mx+b

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3 years ago

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If a line with a slope of -2 crosses the y-axis at (0,3). What is the equation of the line?

baherus [9]

It technically would be y=3x-3 in the y=mx+b formula, but it could also be rewritten 3x-y=3. Hope this helps!

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3 years ago

Can someone help me with this?

jekas [21]

Answer:

$\huge\purple{ x^2 +(y+2)^2 = 4}$

Step-by-step explanation:

Circle is centred at (0, -2)

-> h = 0 & k = - 2

radius of the circle (r) = y-coordinate of the center = - 2

Equation of circle in standard form is given as:

$(x-h)^2 +(y-k)^2 = r^2$

Plugging the values of h, k and r in the above equation, we find:

$(x-0)^2 +[y-(-2)]^2 = (-2)^2$

$\implies\huge\orange{ x^2 +(y+2)^2 = 4}$

This is the required equation of circle.

6 0

2 years ago

What is the ratio 42 to 48 as a fraction in simplest form?

Dominik [7]

42/48 in simplest form is 7/8

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3 years ago

Find the indefinite integral using the substitution provided.

Nady [450]

Answer: $7\text{Ln}\left(e^{2x}+10\right)+C$

This is the same as writing 7*Ln( e^(2x) + 10) + C

=======================================================

Explanation:

Start with the equation $u = e^{2x}+10$

Apply the derivative and multiply both sides by 7 like so

$u = e^{2x}+10\\\\\frac{du}{dx} = 2e^{2x}\\\\7\frac{du}{dx} = 7*2e^{2x}\\\\7\frac{du}{dx} = 14e^{2x}\\\\7du = 14e^{2x}dx\\\\$

The "multiply both sides by 7" operation was done to turn the 2e^(2x) into 14e^(2x)

This way we can do the following substitutions:

$\displaystyle \int \frac{14e^{2x}}{e^{2x}+10}dx\\\\\\\displaystyle \int \frac{1}{e^{2x}+10}14e^{2x}dx\\\\\\\displaystyle \int \frac{1}{u}7du\\\\\\\displaystyle 7\int \frac{1}{u}du\\\\\\$

Integrating leads to

$\displaystyle 7\int \frac{1}{u}du\\\\\\7\text{Ln}\left(u\right)+C\\\\\\7\text{Ln}\left(e^{2x}+10\right)+C\\\\\\$

Be sure to replace 'u' with e^(2x)+10 since it's likely your teacher wants a function in terms of x. Also, do not forget to have the plus C at the end. This is a common mistake many students forget to do.

To verify the answer, you can apply the derivative to it and you should get back to the original integrand of $\frac{14e^{2x}}{e^{2x}+10}$

4 0

2 years ago