A(t)=A0*(1/2)^(t/30)
where t=elapsed years
A0=initial mass at t=0.
To solve this, set up two equations using the information you're given. Let's call our two numbers a and b:
1) D<span>ifference of two numbers is 90
a - b (difference of two numbers) = 90
2) The quotient of these two numbers is 10
a/b (quotient of the two numbers) = 10
Now you can solve for the two numbers.
1) Solve the second equation for one of the variables. Let's solve for a:
a/b = 10
a = 10b
2) Plug a =10b into the first equation and solve for the value of b:
a - b = 90
10b - b = 90
9b = 90
b = 10
3) Using b = 10, plug it back into one of the equations to find the value of a. I'll plug it back into the first equation:
a - b = 90
a - 10 = 90
a = 100
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Answer: The numbers are 100 and 10</span>
The correct answer is:
D. ∠FGE≅∠NMP
Explanation:
The symmetric property states that if two quantities are equal (or congruent), you can "flip" them around the equals sign (or congruence sign).
This means since EFG is congruent to HJK, then HJK is congruent to EFG.
WHERE IS THE MATH PROBLEM
Answer:
Step-by-step explanation: