Solve the inequality. −3y<−14

Mathematics

1 answer:

Artyom0805 [142]2 years ago

3 0

Answer: y>14/3

Step-by-step explanation:

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Annual starting salaries for college graduates with degrees in business administration are generally expected to be between and

kenny6666 [7]

The planning value for the population standard deviation is 4330.

Given the confidence interval 20000 and 35000.

We have to find the planning value of standard deviation.

Standard deviation is measuring dispersion of data. Uniform probability distribution has two bounds a and b. The standard deviation is given by :

s= $\sqrt{(b-a)^{2}/12 }$ .

Annual starting salaries for college graduates be between 20000 and 35000.

It is uniform in the interval so, a=20000, b=35000.

Now we have to just put the values of a and b in the above formula to get the value of standard deviation.

s= $\sqrt{(35000-20000)^{2} /12}$

= $\sqrt{(15000)^{2} /12}$

= $\sqrt{225000000/12}$

= $\sqrt{18750000}$

=4330

Hence the planning values for the population standard deviation is 4330.

Learn more about standard deviation at brainly.com/question/475676

#SPJ1

Question is incomplete as it should includes the confidence interval of $20000 and $35000.

4 0

1 year ago

Find the midpoint of the line y = 3x + 9 on the interval 1 < x < 9.<br> (x, y) = ?

BaLLatris [955]

Answer:

(5, 24)

Step-by-step explanation:

In order to find the midpoint of a line, you need two sets of coordinates. The formula to find the midpoint of a line is $(\frac{x1+x2}{2} ,\frac{y1+y2}{2} )$ , where $x1$ is the x-coordinate of one of the coordinates and $x2$ is the x-coordinate of the second coordinate (and so on for $y1$ and $y2$ ).

In this question, we're not given the two sets of coordinates to find the midpoint from. But we are told there is an interval 1 < x < 9, so first we substitute x=1 into the equation of the line: $y=3$ × $1+9$ = 3 + 9 = 12. So one of the coordinates is (1, 12). Doing the same with x=9, will give us y = 24.