I need help please prettyyyy pleeeeaaaasssseeeee
1 answer:
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THIS IS THE COMPLETE QUESTION
basketball player is shooting a basketball toward the net. The height, in feet, of the ball t seconds after the shot is modeled by the equation h = 6 + 30t – 16t2. Two-tenths of a second after the shot is launched, an opposing player leaps up to block the shot. The height of the shot blocker’s outstretched hands t seconds after he leaps is modeled by the equation h = 9 + 25t – 16t2. If the ball reaches the net 1.7 seconds after the shooter launches it, does the leaping player block the shot?
Yes, exactly 0.6 seconds after the shot is launched.
Yes, between 0.64 seconds and 0.65 seconds after the shot is launched
Yes, between 0.84 seconds and 0.85 seconds after the shot is launched.
No, the shot is not blocked.
Answer:
Yes, between 0.84 seconds and 0.85 seconds after the shot is launched.
Given that the
equation for shot block height h = 9 + 25t – 16t2.
equation for ball height h = 6 + 30t – 16t2.
From the question ,it can be deducted that the shot is made before two tenths of a second or 0.2seconds
CHECK THE ATTACHMENT TO COMPLETE THE DETAILED SOLUTION
Answer:
B)
Step-by-step explanation:
You distribute:
-10 times X minus 3 ( -10*x-3)
Which gives you:
Answer: -10x+30
Hope this helps!
